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AnnZ [28]
3 years ago
7

Assume that the average protein in

Biology
1 answer:
miv72 [106K]3 years ago
7 0

Assume that the average protein in E.coli consists of a chain of 400 amino acids.  Now, a single amino acid present in the protein requires a codon to code for it. A codon consists of 3 nucleotides. This shows that a protein of length 400 amino acids will require, 400 codons to code for it, that is, 1200 (3 x 400) nucleotides are required. We know that the length of the E.coli genome on average is 5 x 10^{6} base pairs.

1200 nucleotides = 1 protein

5 x 10^{6} nucleotides = X no. of proteins

X = \frac{5\times 10^{6} \times 1}{1200} = 4167

The answer is 4167 proteins.

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