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AnnZ [28]
3 years ago
7

Assume that the average protein in

Biology
1 answer:
miv72 [106K]3 years ago
7 0

Assume that the average protein in E.coli consists of a chain of 400 amino acids.  Now, a single amino acid present in the protein requires a codon to code for it. A codon consists of 3 nucleotides. This shows that a protein of length 400 amino acids will require, 400 codons to code for it, that is, 1200 (3 x 400) nucleotides are required. We know that the length of the E.coli genome on average is 5 x 10^{6} base pairs.

1200 nucleotides = 1 protein

5 x 10^{6} nucleotides = X no. of proteins

X = \frac{5\times 10^{6} \times 1}{1200} = 4167

The answer is 4167 proteins.

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Coat color in rabbits is under the control of a single gene with
Mashcka [7]

Answer: a) Cch x   Ccch

               b)  Ccch x  Cc

               c)   Cch  x   cchch

               d)  cchc x   chc

Explanation:

<u>Data</u>:

  • Coat color in rabbits is under the control of a single gene with

four alleles: C (full gray color); cch (chinchilla, light gray); ch

(Himalayan, white with black extremities); and c (albino, absence

of pigmentation).

  • The dominance hierarchy is represented as: C >cch > ch > c.

<u>Possible genotypes</u>:

  • <em>For full gray color</em>: CC (Gray), Ccch (Gray-2), Cch (Gray-1), Cc (Gray-3). The allele <em>"C" dominates over the other three alleles</em>, so in every combination where "C" is present, the animal will be fully grayed.
  • <em>For light gray color/Chinchilla</em>: cchcch (Chinchilla), cchch (Chinchilla-1), cchc (Chinchilla-2). The allele <em>"cch" dominates over "ch" and "c"</em>, <em>but not over "C"</em>. So if the allele "C" is combined with "cch", the animal will be fully grayed, but in any other combination with "cch", the animal will be light grayed.
  • <em>For white with black extremities/Himalayan</em>: chch (Hymalayan), chc (Hymalayan-1). The allele <em>"ch" that determines the Himalayan color is only dominant over the allele "c"</em>. But in combination with any other allele, "ch" behaves as a recessive one.
  • <em>For albino</em>: cc. In the presence of any of the other alleles, the allele <em>"c" always behaves as a recessive one.</em> The only possibility of getting an albino animal is if "c" combines with another "c".

<u>Crosses</u>:

a) Gray-1 x gray-2

    3/4 gray : 1/4 chinchilla

   

   Parental)       C ch        x        C cch

   Gamates)     C        ch           C         cch

Punnet Square)              C              cch

                           C        <em>CC</em>           <em>Ccch</em>

                           ch       <em>Cch</em>         <em>cchch</em>

F1 Genotype)    1/4  <em>CC</em>  

                          1/4 <em>Cch</em>

                          1/4 <em>Ccch</em>

                          1/4 <em>cchch</em>

F1 Phenotype)   3/4 Fully Gray animals (CC, Cch, Ccch)

                          1/4 Chinchilla animals (cchch)

b) Gray-2 x gray-3

    3/4 gray : 1/4 chinchilla

 

Parental)          C cch      x     C c

   Gamates)    C    cch           C    c

Punnet Square)            C              cch

                           C      <em>CC            Ccch</em>

                           c       <em>Cc            cchc</em>

F1 Genotype)    1/4  <em>CC</em>  

                         1/4 <em>Cc</em>

                         1/4 <em>Ccch</em>

                          1/4 <em>cchc</em>

F1 Phenotype) 3/4 Fully Gray animals (CC, Cc, Ccch)

                        1/4 Chinchilla animals (cchc)

c) Gray-1 x chinchilla-1

    1/2 gray : 1/4 chinchilla : 1/4 himalayan

Parental)           C ch        x        cchch

   Gamates)    C        ch           cch         ch

Punnet Square)           C              ch

                          cch    <em> Ccch       cchch</em>

                             ch      <em> Cch         cchch</em>

F1 Genotype)    1/4  <em>Ccch  </em>

                              1/4 <em>Cch</em>

                              1/4 <em>cchch</em>

                              1/4 <em>chch</em>

F1 Phenotype) 2/4=1/2 Fully Gray animals (Ccch, Cch)

                             1/4 Chinchilla animals (cchch)

                             1/4 Himalayan animals (chch)

d) Chinchilla-2 x himalayan

   1/2 chinchilla : 1/4 himalayan : 1/4 albino

Parental)          cchc        x         chc

   Gamates)    cch      c            ch        c

Punnet Square)           cch              c

                           ch      <em> cchch          chc</em>

                             c        <em>cchc            cc</em>

F1 Genotype)    1/4  cchch  

                         1/4 cchc

                          1/4 chc

                          1/4 cc

F1 Phenotype) 2/4=1/2 Chinchilla animals (cchch, cchc)

                             1/4 Himalayan animals (chc)

                             1/4  Albino animals (cc)

6 0
3 years ago
Prokaryotic and eukaryotic cell components
vodomira [7]

Answer:

cells of both prokaryotic eukaryotic is a plasma membrane  call cytoplasm

Explanation:

3 0
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Over a lifetime, a diet high in cholesterol can cause blood vessels to become less elastic. WHICH CAN LEAD TO HIGH BLOOD PRESSUR
Wewaii [24]
I think it is B.heat stroke
8 0
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Which statement is NOT true about all living things?​
kompoz [17]

Answer:

living things do not reproduce

8 0
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Which of the following is related to the likelihood that a mother develops postpartum depression?
Veronika [31]

Answer:

Option D

Explanation:

Postpartum depression is majorly experienced in woman who has recently entered into motherhood. This form of depression arises because of the complications involved in a child birth. It is strongly driven by sudden changes that come up in the life of a woman after becoming mother such as – loss of job, responsibility of child, tight life schedule etc. some common symptoms of this problem include – mood swing, anxiety, sleeplessness, crying etc.  

Hence, option D is correct

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