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3 years ago

What’s the value of the missing angle

Mathematics

2 answers:

Arada [10]3 years ago

8 0

Answer:

The answer is 120

Dvinal [7]3 years ago

4 0

The value of the missing angle I’m not sure but I think it’s, 120 that’s the best I could think of

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The manufacturing cost of a cell phone was $136. Sellers first marked up the cost by 25 percent. Sales were poor, so sellers dec

vfiekz [6]

The <em><u>correct answer</u></em> is:

C.) old price was $170, new price is $159.12

Explanation:

The original price was $136. For a 25% markup, this means the amount of markup is 0.25(136) = 34. This makes the new price 136+34 = $170.

When they mark the price down to a 17% markup, this means the price is 0.17(136)+136 = 23.12+136 = $159.12.

6 0

3 years ago

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Which is true of a population in a statistical survey? Check all that apply.

Fofino [41]

Answer: b and d

Step-by-step explanation:

yw!

3 0

3 years ago

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In an orienteering class, you have the goal of moving as far (straight-line distance) from base camp as possible by making three

RUDIKE [14]

Answer:

The greatest distance we can be from the base camp at the end of the third displacement is 6.69 km

Step-by-step explanation:

We can think of each displacement as a vector, with a given magnitude and direction.

A vector can be written using its x and y coordinates like this

$\vec{t}=(x, y)$

So, for the displacements a and c their vector coordinates would be:

$\vec{a}=(2, 0)$

$\vec{c}=(-1, 0)$

As the b displacement has an angle of 30° toward the north from due east, we can find its x and y coordinates using the following formulas:

$x=(magnitude)*cos(angle)$

$y=(magnitude)*sin(angle)$

Note: the angle in the formula is the one formed with the east measured counterclockwise.

So, the x and y coordinates for the b displacement will be:

$\vec{b}=(2*cos(30), 2*sin(30))$

As the vector additon is commutative, the order won't affect the final position. Nevertheless, any change in the direction of any displacement will change the final position. So, in order to find the combination greatest distance we should calculate the following additions and find the one with the greatest magnitude:

$\vec{R_{1}} =\vec{a}+\vec{b}+\vec{c}$

$\vec{R_{2}} =\vec{a}-\vec{b}+\vec{c}$

$\vec{R_{3}} =\vec{a}+\vec{b}-\vec{c}$

$\vec{R_{4}} =\vec{a}-\vec{b}-\vec{c}$

Each resultant vector can be found adding each component. Afterwards, the magnitude can be found using the following formula:

$|\vec{R}|=\sqrt[ ]{(R_{x})^2 +{(R_{y})^2}}$

Now, let's calculate!

$\vec{R_{1}} =\vec{a}+\vec{b}+\vec{c}$

$R_{1_x}} =2+2*cos(30)-1=2.73$

$R_{1_y}} =0+2*sin(30)+0=1$

$\vec{R_{1}}=(2.73,1)$

$|\vec{R_{1}}|=\sqrt[ ]{(2.73)^2 +{(1)^2}}=3.86$

$\vec{R_{2}} =\vec{a}-\vec{b}+\vec{c}$

$R_{2_x}} =2-2*cos(30)-1=0.73$

$R_{2_y}} =0-2*sin(30)+0=-1$

$\vec{R_{2}}=(-0.73,-1)$ }

$|\vec{R_{2}}|=\sqrt[ ]{(-0.73)^2 +{(-1)^2}}=1.03$

$\vec{R_{3}} =\vec{a}+\vec{b}-\vec{c}$

$R_{3_x}} =2+2*cos(30)+1=4.73$

$R_{3_y}} =0+2*sin(30)-0=1$

$\vec{R_{3}}=(4.73,1)$

$|\vec{R_{3}}|=\sqrt[ ]{(4.73)^2 +{(1)^2}}=6.69$

$\vec{R_{4}} =\vec{a}-\vec{b}-\vec{c}$

$R_{4_x}} =2-2*cos(30)+1=1.26$

$R_{4_y}} =0-2*sin(30)-0=1$

$\vec{R_{4}}=(1.26,-1)$

$|\vec{R_{4}}|=\sqrt[ ]{(1.26)^2 +{(-1)^2}}=1.79$

So, after all the calculation, we can know for sure that the vector $\vec{R_{3}}$ has the biggest magnitude. Then, the greatest distance we can be from the base camp at the end of the third displacement is 6.69 km

7 0

3 years ago

A car travels 320 miles in 7.5 hours. If the car continues at the same rate, how far

Serggg [28]

Answer:

Step-by-step explanation:

put that info in a table then cross multiply and divide.

the answer is 512

3 0

3 years ago

I need help!! Thx if answer :)

MAXImum [283]

Answer:

-1050

Step-by-step explanation:

descending means going down so 2100 is the big number and its negative to if you do -2100 divided by 2 then you will get -1050. I'm not sure about the second part. But good luck!

8 0

3 years ago

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