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77julia77 [94]
3 years ago
12

Box 1 measures 6 cmon width, 12 cm in length and 4 cm in height. The height is doubled to 8cm to produce a larger box, Box 2 Whi

ch phrase accurately describes the volume of Box 2 in relation to Box 1

Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer: put A

Step-by-step explanation:

Put A cause 1 can’t be measure so you have to add 4 .

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SOMEONE HELP ME ON THESE TWO QUESTIONS PLEASE
Anika [276]

1st Answer:

$25

Step-by-step explanation:

You have to subtract the installation fee from the total fee.

685-85=600

If it is for 2 years, that is 24 months, so divide

600/24=$25

2nd Answer:

36 and 37

Step-by-step explanation:

Consecutive means they fall directly next to each other EX: 1, 2, 3, 4.... are consecutive numbers

36 and 37 are consecutive

36+37=73

8 0
3 years ago
if 12 shirts of equal size can be prepared from 27m cloth what is the length of cloth required for each shirt
puteri [66]
27/12=2.25

So ur answer is 2.25m

hope it helped and dont forget to mark as the branliest  :) 

7 0
3 years ago
Use the figure to find the angle m
nordsb [41]

Answer:

Measure of angle M = 41°

Step-by-step explanation:

From the figure attached,

NM ≅ NO [Given]

Therefore, ∠O ≅ ∠M [Opposite angle of the equal sides]

By triangle sum theorem,

m∠O + m∠N + m∠M = 180°

m∠O + m∠N + m∠O = 180° [Since, ∠M ≅ ∠O]

By substituting the values of the given angles,

(4y - 15)° + (7y)° + (4y - 15)° = 180°

(15y - 30) = 180

15y = 210

y = 14

Therefore, m∠M = (4y - 15)°

                           = 4(14) - 15

                           = 56 - 15

                           = 41°

6 0
3 years ago
10,000 round to the nearest ten thousand
wlad13 [49]

Answer:

i think it would be 10,000

I hope it helped!

5 0
3 years ago
Read 2 more answers
Use the quadratic formula to find the solution to the question <br> 3x^2-10x+5=0
nlexa [21]

Answer:

x_{1}  = \frac{5 + \sqrt{10} }{3}  and x_{2} = \frac{5 - \sqrt{10} }{3}

Step-by-step explanation:

3x^2-10x+5=0

x_{1} = \frac{10 + \sqrt{10^{2}-4*3*5 } }{2*3}                  x_{2} = \frac{10 - \sqrt{10^{2}-4*3*5 } }{2*3}

x_{1} = \frac{10 + \sqrt{100-60} }{6}                      x_{2} = \frac{10 - \sqrt{100-60} }{6}

x_{1} = \frac{10 + \sqrt{40} }{6}                            x_{2} = \frac{10 - \sqrt{40} }{6}

x_{1} = \frac{10 + 2\sqrt{10} }{6}  / 2                    x_{2} = \frac{10 - 2\sqrt{10} }{6}  / 2

x_{1}  = \frac{5 + \sqrt{10} }{3}                             x_{2} = \frac{5 - \sqrt{10} }{3}

3 0
3 years ago
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