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77julia77 [94]
3 years ago
12

Box 1 measures 6 cmon width, 12 cm in length and 4 cm in height. The height is doubled to 8cm to produce a larger box, Box 2 Whi

ch phrase accurately describes the volume of Box 2 in relation to Box 1

Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer: put A

Step-by-step explanation:

Put A cause 1 can’t be measure so you have to add 4 .

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Last question was inncorrectly typed:1.A sample of students who has taken a calculus test has a mean =78.2, mode =67, median 67.
vampirchik [111]

Answer:

(A) The data set of the sample of students who has taken a calculus test is right skewed.

(B) The average of female students in the class is 66.

Step-by-step explanation:

(A)

For a left skewed distribution the Mean < Median < Mode.

For a right skewed distribution the Mean > Median > Mode.

For a symmetric distribution the Mean = Median = Mode.

Given: Mean = 78.2, Median = 67 and Mode = 67

In this case the mean of the data is more than the median and mode.

Mean = 78.2>Median = Mode = 67

Thus, the data set of the sample of students who has taken a calculus test is right skewed.

(B)

Total number of student (n) = 35

Combined average (\mu_{c}) = 70

Number of male student (n_{M}) = 20

Average of male students (\mu_{M}) = 73

Number of female student (n_{F}) = 15

Average of female students = \mu_{F}

The formula to compute the combined average is:

\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}

Compute the value of \mu_{F} as follows:

\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}\\70=\frac{(20\times73)+(15\times\mu_{F})}{20+15}\\ 70\times35=1460+(15\times\mu_{F})\\\mu_{F}=\frac{2450-1460}{15} \\=66

Thus, the average of female students in the class is 66.

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4 years ago
If m DBC = 25x+ 7 and m TBC = 12x+ 5 =, find the degree measures of TBC, DBT, and DBC.
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Petes dad usually deposits $25 into his bank account overy week for the next weekho der more than the usual 25. and he wants the
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Answer:

8(25+x) >500 ; x>37

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3 years ago
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