Will ran the longest
He ran for 56.57 yards, 13.56 yards longer than James.
Step-by-step explanation:
Step 1 :
Will ran the diagonal across a square field measuring 40 yards in each side.
The diagonal of a square can be obtained by the square root of the sum of the squares of its 2 sides [Because it forms the hypotenuse of a right angle triangle]
Hence when the side is 40 yards , the diagonal would be
So Will ran for 56.57 yards
Step 2 :
James ran the diagonal of a rectangular field with 25 yards length and 35 yards width.
The diagonal of the rectangle can be obtained by the square root of the sum of squares of its length and width.
Hence when the length is 25 yards and width is 35 , the diagonal would be
yards
So James ran for 43.01 yards
Step 3 :
Will ran for 56.57 yards and 43.01 yards.
Hence Will ran for longer distance of 56.57 yards, which is 13.56 yards more than James.
Answer:
1) y = 12
2) x = 4
3) w = -3
4) k = -35
Step-by-step explanation:
Answer:
1. initial point is (2, 4)
reflected point is (-2, 4)
the coordinates are similar because they involve the same numbers, however, with the reflection across the Y axis, the X point became negative.
2. initial point is (2, 4)
reflected point is (2, -4)
again, same numbers but the X value becomes negative
Hope this helps!
Answer:
oven, whisk, pan
Step-by-step explanation:
Answer:
Number of quarters → 15
Number of dimes → 2
Step-by-step explanation:
Let the number of dimes I have = y
And number of quarters = x
Since, I have amount in my pocket = $2
Therefore, 0.10y + 0.25x = 2
100(0.10y + 0.25x) = 100×2
25x + 10y = 200
5x + 2y = 40
2y = -5x + 40
y = -2.5x + 20 ---------(1)
Total number of coins in my pocket = 17
x + y = 17
y = -x + 17 ---------(2)
By using a graphing calculator we can graph these two lines (As attached)
Solution of the given system of equations will be the point of intersection of these lines.
Solution → (2, 15)
Number of quarters → 15
Number of dimes → 2
