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otez555 [7]
3 years ago
12

describe the following number patterns in your own words and state the constant difference or constant ratio if there is one​

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Step-by-step explanation:

awq-pzcq-mje

girls

come

to

see

my

22cm

sperm

fast

girl

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a die rolled. the set of equally likely outcomes is 1 ,2, 3, 4, 5, 6. find the probability of getting a 10.
Sidana [21]

Answer:

1 in 12

Step-by-step explanation:

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5 0
3 years ago
A linear inequality in two variables has an ___________ number of solutions.
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An Infinite Number of solutions is the answer! LMK if you have any more questions, and have a nice day/evening.

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3 years ago
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Round 5.9496 to the nearest thousandth
Evgesh-ka [11]

Answer:

5.95

Step-by-step explanation:

that is because 96 is rounded too 100

so its 5.9500 = 5.95

4 0
3 years ago
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What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
3
Alex17521 [72]

Answer:

A

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6 0
2 years ago
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