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3 years ago

Find the value of x to the nearest tenth.

Mathematics

1 answer:

nlexa [21]3 years ago

8 0

Answer:

x = 14.7

Step-by-step explanation:

Using the sine rule

$\frac{a}{sin(A)} = \frac{b}{sin(B)} = \frac{c}{sin(C)}$

Substitute the given values.

$\frac{7}{sin(20)} = \frac{x}{sin(46)}$

Rearrange the equation to get x on it's own.

$\frac{7sin(46)}{sin(20)} = x$

x = 14.72246211

x = 14.7 (1dp)

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Find the value of x (look at screenshot below)

Black_prince [1.1K]

Answer:

x = 25

Step-by-step explanation:

120 = 70 + 2x

120 - 70 = (70 - 70) + 2x

50 = 2x

50/2 = 2x/2

x = 25

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Step-by-step explanation:

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2 years ago

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M+2/3=1/4m-1 what the formula used to find the value of m?

zimovet [89]

Answer:

The value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

Solution:

Given, expression is $m+\frac{2}{3}=\frac{1}{4 m}-1$

Now, we have to solve the above given expression.

$\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1$

By multiplying the equation with m, we get

$\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}$

$\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}$

Now, let us use quadratic formula

$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in our problem, a = 12, b = 20, c = -3

$\begin{array}{l}{m=\frac{-20 \pm \sqrt{20^{2}-4 \times 12 \times(-3)}}{2 \times 12}} \\\\ {=\frac{-20 \pm \sqrt{400+144}}{24}} \\\\ {=\frac{-20 \pm \sqrt{544}}{24}} \\\\ {=\frac{-20 \pm 4 \sqrt{34}}{24}=\frac{-5 \pm \sqrt{34}}{6}} \\\\ {=\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}}\end{array}$

Hence the value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

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