Given u = ⟨1, 3⟩, v = ⟨2, 1⟩, and cos(ϴ) = StartFraction StartRoot 2 EndRoot Over 2 EndFraction , where ϴ is the angle between t
2 answers:
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Hi there!
There are 3 parts to this equation:
f(x)
f(x+1)
4f(x)
We must first determine these three parts separately.
<u>1) f(x)</u>
We're given that :
⇒ :
<u>2) f(x+1)</u>
Now, we must find f(x+1). To do so, add 1 to x in the original function :
⇒
<u>3) 4f(x)</u>
To find 4f(x), multiply the original function by 4:
:
<u>4) Put it all together</u>
Now, plug each of the three parts into the equation :
Factor the left side
Divide both sides by 3^x
Because this equation is true, is therefore true.
I hope this helps!
We'll have an attached picture (Ignore the labeling). We can easily observe that DF (in the picture BC), cannot be equal to the radius. Then, we cannot also claim that RD=RF. And since we are talking about the tangent segment, we'll have a right triangle. The correct answer is C)
