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3 years ago

9

Please understand the explanation

1 answer:

aivan3 [116]3 years ago

4 0

<em> $answer = 12.56 \: square \: km\\ radius = 4km \\ area \: of \: quarter \: circle = \frac{\pi {r}^{2} }{4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times {4}^{2} }{4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times 16}{4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12.56 \: square \: km \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$ </em>

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Make a table of values and graph the solutions of the given equation.

jonny [76]

Answer: 3
Because X=1
2x1=2
2+1=3

3 0

3 years ago

What is the perimeter?

Vladimir79 [104]

Answer:

Perimeter = 22 units

Area = 30 units squared

Step-by-step explanation: To find the perimeter of this figure, add the lengths of the rectangle's four sides (5+6+5+6=22). To find the area of this figure, multiply the length and width of the rectangle (5x6=30).

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2 years ago

For the geometric sequence of a1=2 and r=2 find a5

Brrunno [24]

Answer:

$a_5 = 32$

Step-by-step explanation:

The nth term for the geometric sequence is given by:

$a_n = a_1 \cdot r^{n-1}$

where,

$a_1$ is the first term

r is the common ratio

n is the number of terms.

As per the statement:

For the geometric sequence of $a_1=2$ and r=2

We have to find $a_5$

for n = 5;

$a_5=a_1 \cdot r^{n-1}$

Substitute the given values we have;

$a_5 = 2 \cdot 2^4 = 2 \cdot 16$

⇒ $a_5 = 32$

Therefore, the value of $a_5$ is, 32

3 0

3 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago

Add then divide.<br> Evaluate<br> (7.3 X 10) + (2.4 X 107)<br> (4 X 104)

Deffense [45]

Answer:

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Step-by-step explanation:

(7.3 X 10) + (2.4 X 10^7)

(4 X 10^4)

= 73 + 24000000

40000

= 24000073

40000

= 6.0 x 10^2

4 0

3 years ago