Ask question

Ask question

All categories

3 years ago

9

Please understand the explanation

1 answer:

aivan3 [116]3 years ago

4 0

<em> $answer = 12.56 \: square \: km\\ radius = 4km \\ area \: of \: quarter \: circle = \frac{\pi {r}^{2} }{4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times {4}^{2} }{4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times 16}{4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12.56 \: square \: km \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$ </em>

You might be interested in

Ty received test grades of 82%, 74%, 76%, 76%, and 74%.

Nikitich [7]

Answer:

a) To earn C he needs at least 68 and less than 98

b) No, he couldn't make it.

Step-by-step explanation:

I. His avg value is (382 + x)/6

I pick a random number and that gave

(68 => to reach 75) and (98 => to reach 80)

So that makes he needs at least 68 and less than 98

II. The reason why he cannot make it is

if 100 is 100%

= (100 + 382)/6

= 80.33 That's impossible to reach 90

Hope that help :)

7 0

3 years ago

Use mental math to solve the problem 8.02 − 5.98

Zinaida [17]

Round off 8.02 to 8 and 5.98 to 6. Then subtract: 8 - 6 = 2 (approximately)

4 1

3 years ago

Read 2 more answers

Jenny has been saving quarters in a piggy bank since she was born. She currently has 192 quarters in her piggy bank. She decides

Mrac [35]

Answer:

D) She has a total of $62 in the piggy bank.

Step-by-step explanation:

Jenny has been saving quarters in a piggy bank since she was born.

She decides to add 56 more quarters so that she can buy a $65 phone.

So she has 192 + 56 = 248 quarters currently.

1 quarter is equivalent to $0.25

248 quarters equals;

$\frac{248}{1}$ × $0.25 = $62

So Jenny has a total of $62 in the piggy bank.

5 0

3 years ago

BRAINIEST QUICKKKK!!!! You guys are really the best

wariber [46]

Use photo math it will be easier

3 0

3 years ago

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

fenix001 [56]

Answer:

Step-by-step explanation:

Given that

$\alpha =2.5$ , $\beta =220$

The weibull distribution with parameters $\alpha \ \ and \ \ \beta$

where $\alpha =0 \ \ , \beta =0$

$F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha &x\geq 0\\0&x$

Then,

$F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x$

A) The probability that a specimen's lifetime is at most 250 is

$P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564$

The probability that the specimen's life time is more than 300 is

$P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}$

$=e^-^{(300/220)^{2.7}$

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

$P(100$

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

$P(X>x)=0.50\\\\1-P(X$

x = 192.07

7 0

3 years ago