Sj2dg3h3fvehdvddddddddddddd-=
1 answer:
Answer:
= 5
Step-by-step explanation:
From the given diagram we are required to find the length of
The given parameters are;
ΔABC and ΔCDA are congruent
The length of = 5
The length of = 7
The length of = 4
From ΔABC ≅ ΔCDA, we have;
=
By reflexive property
∴ = 5 is either equal to
or
However, = 4, therefore,
≠
We can then have;
=
= 5.
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Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).
Answer:
the answer is in the attached image below
Step-by-step explanation:
