Answer:
9.60 dollars tip is $1.60
Step-by-step explanation:
Answer:
solution 1= 40ml
solution 2= 160ml
Step-by-step explanation:
%alcohol= amount of alcohol/total solutionx100
0.52x200=104ml of alcohol present
0.2x L=0.2Lml of alcohol in solution one
0.6 x M=0.6Mml of alcohol in solution two
1st equation
0.2L+0.6M=104ml alcohol
times 10 to get whole
2L+6M=1040ml
2nd
same for this equation
10L+10M=2000ml
10L+10M=2000
2L+6M=1040
elimination method
=20L+20M=4000
-
=20L+60M=10400
-40M=-6400
M=160ml
2L+6 (160)=1040
2L=1040-960
2L=80
L=40ml
Answer:
Many answers, look below :)
Step-by-step explanation:
24.
(x)=2x^5+6x^4
June: 30-6=24
July: 31
August:31
September:30
October: 8
Total=24+31+31+30+8=124 days
Discount period:
The period of time between the date a bill of exchange is drawn and the date on which payment is due.
So discount period = 200-124=76 days
<h3>
Answer:</h3>
- <u>20</u> kg of 20%
- <u>80</u> kg of 60%
<h3>
Step-by-step explanation:</h3>
I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.
That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.
_____
<em>Using an equation</em>
If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...
... 0.60x + 0.20(100 -x) = 0.52·100
... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20
... x = 32/0.40 = 80 . . . . . kg of 60% alloy
... (100 -80) = 20 . . . . . . . .kg of 20% alloy