48
The answer to the question is 48
<span>The right information from the figure is:
AU = 20x + 108,
UB = 273,
BC = 703,
UV = 444,
AV = 372 and
AC = 589
The similarity of the two triangles leads to:
[AB] / [AC] = [AU] / [AV]
[AB] = [AU] + [UB] = 20x + 108 + 273 = 20x + 381
=> (20x + 381) / (589) = (20x + 108) / 372
Now you can solve for x.
(372)(20x + 381) = (20x + 108)(589)
=> 7440x + 141732 = 11780x + 63612
=> 11780x - 7440x = 141732 - 63612
=> 4340x = 78120
=> x = 18
Answer: x = 18
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The answer is 20x23=45 hope this helps byeeee
Answer:
x = 6, y = 4
Step-by-step explanation:
The diagonals of a parallelogram bisect with each other at the point of intersection with equal sides across the point of intersection.
- DH = HF ⇒ x + 2 = 2y
- GH = HE ⇒ 4x - 3 = 5y + 1
x + 2 = 2y,
4x - 3 = 5y + 1
x = 2y - 2,
4(2y - 2) - 3 = 5y + 1
x = 2y - 2,
8y - 8 - 3 = 5y + 1
x = 2y - 2,
8y - 11 = 5y + 1
x = 2y - 2,
8y - 5y = 11 + 1
x = 2y - 2,
3y = 12
x = 2y - 2,
y = 4
x = 2*4 - 2,
y = 4
x = 6,
y = 4
If you want to add radicals then radicals should be same as variables in polynomial expressions. If radicals are not equal in nature then we cannot add them. In the case of polynomials, if the variables are not same then we cannot add them. The variables should have the same exponents over them.
