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3 years ago

How are radical expressions and polynomial expressions similar?

1 answer:

mote1985 [20]3 years ago

5 0

If you want to add radicals then radicals should be same as variables in polynomial expressions. If radicals are not equal in nature then we cannot add them. In the case of polynomials, if the variables are not same then we cannot add them. The variables should have the same exponents over them.

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Mariko has 63 photos in her photo book.that is 23 fewer photos than Sharon has.how many photos does Sharon have?

solmaris [256]

Answer: 86 photos

Step-by-step explanation:

This is because since Mariko has 23 fewer photos than Sharon this means that Sharon's photos must be greater.

63 + 23 = 86

= 86 photos

6 0

3 years ago

What is the answer to 7.26 x 106 ft

Diano4ka-milaya [45]

Answer:

769.56

Step-by-step explanation:

its like doing 726 times 106 then just move the decimal. and i looked it up

7 0

3 years ago

10 tens and 10 ones equals

jenyasd209 [6]

Answer:

110 is the answer because 10 tens equal 100 and 10 ones equal 10

Step-by-step explanation:

8 0

3 years ago

Perpendicular to the line 4x - 6y + 7 = 0 , passing through (3, 4) .

PilotLPTM [1.2K]

Answer:

The equation of line perpendicular to given line passing through (3,4) is:

$y = -\frac{3}{2}x+\frac{17}{2}$

Step-by-step explanation:

Given equation of line is:

$4x - 6y + 7 = 0$

Given equation is in standard form. It has to be converted into slope-intercept form to extract slope from the equation.

So,

$4x+7 = 6y\\6y=4x+7\\\frac{6y}{6} = \frac{4x+7}{6}\\y = \frac{4}{6}x+\frac{7}{6}\\y=\frac{2}{3}x+\frac{7}{6}$

The standard form of slope-intercept form of equation is:

$y=mx+b$

Here, the co-efficient of x is the slope of the line.

So the slope of given line is: 2/3

m = 2/3

The product of slopes of two perpendicular lines is -1

Let m1 be the slope of line perpendicular to given line

Then

$m.m_1 = -1\\\frac{2}{3} . m_1 = -1\\m_1 = -1*\frac{3}{2}\\m_1 = -\frac{3}{2}$

The equation of perpendicular will be:

$y = m_1x+b$

Putting the value of slope

$y = -\frac{3}{2}x+b$

To find the value of b, putting (3,4) in the equation

$4 = -\frac{3}{2}(3)+b\\4 = -\frac{9}{2}+b\\b = 4+\frac{9}{2}\\b= \frac{8+9}{2}\\b=\frac{17}{2}$

So the equation of line perpendicular to given line passing through (3,4) is:

$y = -\frac{3}{2}x+\frac{17}{2}$

7 0

3 years ago

Please help im really struggling what is the surface area of this shape?

Semenov [28]

Answer:

1480 in^2

Step-by-step explanation:

We can number the surfaces so we can talk about them. Starting with the very top horizontal surface, call it #1. Then the vertical surface to its right (clockwise) is #2; the lower horizontal surface you can see is #3, and the rightmost end vertical surface is #4. The bottom horizontal surface on which the figure rests is #5, and the left vertical surface you can't see is #6. Call the front vertical L-shaped surface #7, and the back vertical L-shaped surface #8.

These can all be "unfolded" into the figure shown in the attachment. (Each grid square in the attached figure is 5 inches.)

Surfaces 1–6 constitute a rectangle that is 88 inches long and 10 inches wide. The length (88 inches) is the perimeter of the L-shaped front (and back) surfaces (7 and 8). The width is the front-to-back width of the shape, marked as 10 inches at the lower right of the given figure.

The areas of the two L-shaped surfaces can be calculated several ways. One way is to recognize the L-shape as a 20 in × 24 in rectangle with a 12 in × 15 in rectangle removed from it. Another way to calculate the area is to consider it to be two trapezoids (as cut by the dashed line JV in the attached figure).

___

The discussion above and the attached figure (net) give the information we need to calculate the surface area.

The area of the central pink net is ...

(10 in)×(88 in) = 880 in².

The area of one golden L-shape is ...

(20 in)×(24 in) - (12 in)×(15 in) = 480 in² -180 in² = 300 in²

Then the total surface area is that of the central (pink) rectangle and two (2) (golden) L-shapes, or ...

total area = 880 in² + 2×300 in²

total area = 1480 in²

_____

Comment on the L as trapezoids

The dimensions of the edges of the L-shapes are shown in the attachment. They are computed using the information in the given figure and by subtracting heights or lengths to find the unknown dimensions.

The upper left trapezoid has a height of 9 units and bases of 12 and 20. Its area is given by the formula

A = (1/2)(b1 +b2)h = (1/2)(12 +20)·9 = 144 . . . . in²

The lower right trapezoid has a height of 8 units and bases of 24 and 15. Its area is given using the same formula

A = (1/2)(24 +15)·8 = 156 . . . . in²

Then the total area of one L-shape is the sum of these areas, or ...

L-shape area = 144 in² + 156 in² = 300 in² . . . . . same as above

7 0

3 years ago