13, 6+7=13 thats my answer :D
Tbh i’m just trying to get points
A=3
B=4
C=5
Substitute 3 in for 'a' in the equation, and 5 in for 'c' in the equation to get 17.
Answer:
R = ![\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26-2%5C%5C1%26-3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
P - Q + R = I ( I is the identity matrix )
-
+ R =
( subtract corresponding elements )
+ R = ![\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R = ![\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
R =
-
= ![\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26-2%5C%5C1%26-3%5C%5C%5Cend%7Barray%7D%5Cright%5D)