Answer: No
Step-by-step explanation:
I can’t think of one but if you have a pegboard there is a formula called Pick’s Formula
Answer:
21
Step-by-step explanation:
just because whsusjeej
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
#SPJ1
Answer:
m = 32
Step-by-step explanation:
the answer is c: .... 72+8w
