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denpristay [2]
3 years ago
13

-3(4+g) - 2(-5x+8) Simplify

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

10x-3g-28

Step-by-step explanation:

You first want to distribute the number in front into the parenthesis:

-12-3g+10x-16

Now just simplify the whole numbers:

-28-3g+10x

Now put it in alphabetical order:

10x-3g-28

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The 10,000-meter long-distance running event in the summer Olympics is approximately 6.2 miles. Which equation could be used to
Dima020 [189]

Answer:

t = 6.2/s miles/minute

Step-by-step explanation:

Average speed is defined as the rate of change in distance of a body. Mathematically; speed = Distance/Time

Given the distance of the runner in miles to be d = 6.2miles

Time taken = t

Average speed = s

To express t in terms of the average speed s and distance of 6.2miles, we will substitute the values into the formula;

s = D/t

Substituting D = 6.2miles into the formula;

s = 6.2/t

Cross multiply

St = 6.2

Divide both sides by 's'

st/s = 6.2/s

t = 6.2/s

Hence, the equation that could be used to determine the time, t, it takes to run 10,000 meters as a function of the average speed, s, of the runner where t is in minutes and s in miles per minute is t = 6.2/s miles/minute

8 0
3 years ago
The graph of a system of equations with the same slope and the same y-intercepts will have no solutions.
Rasek [7]
If 2 equations have the same y-intercept, they are overlapping, which means they have infinite solutions. So there is no way that 2 equations with the same y-intercept will have no solution. Thus your answer is: C)Never. 
4 0
4 years ago
Read 2 more answers
2. Create an estimated probability distribution for the time teens spend texting.
Furkat [3]

Answer:

<u><em>Hours</em></u>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<u><em>Frequency</em></u>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.

Hours          0     0.5    1.0   1.5  2.0   2.5  3.0  3.5  4.0  4.5  5.0

Frequency  170  82    220  153  92   58   40    15  12   18    10

Step-By-Step Explanation:

As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.

As given in the problem statement,

<em><u>Total Sample Size = 870</u></em>

To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:

Estimated Probability Distribution (Frequency*)=\frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}

<u><em>For Example:</em></u>

Estimated probability distribution that teens spend 0 hours texting=\frac{170}{870} =0.20

Similarly

Estimated probability distribution that teens spend 0.5 hours=\frac{82}{870} =0.09

Using the same formula we get:

<em><u>Hours</u></em>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<em><u>Frequency</u></em>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

(<em>Note: Frequency* is the estimated probability distribution)</em>

4 0
3 years ago
Read 2 more answers
(24+11) times W <br><br> Simplify the variable expression
olasank [31]
I think it’s 35w because you distribute: 24w+11w ) and then you add.
3 0
3 years ago
Read 2 more answers
Suppose that you live in a community that has 125,000 households. Among these households, 50,000 have traditional landline telep
DedPeter [7]

Answer:

0.4 = 40% probability that the second household selected will have a traditional landline telephone

Step-by-step explanation:

A probability is given by the number of desired outcomes divided by the number of total outcomes.

We have that:

125,000 households

50,000 have traditional landlines telephones.

The first household selected does not have a traditional landline telephone.

Now we have 125000 - 1 = 124,999 households, and 50,000 have traditional landlines telephones.

What is the probability that the second household selected will have a traditional landline telephone

p = \frac{50000}{124999} = 0.4

0.4 = 40% probability that the second household selected will have a traditional landline telephone

6 0
3 years ago
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