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4 years ago

(a) P(1,0). Q(2,-5), R(-3, -5) What triangle is this

Mathematics

1 answer:

dusya [7]4 years ago

5 0

This is a scalene obtuse triangle

An obtuse triangle is a triangle with an angle greater than 90 degrees, A scalene triangle is a triangle that has three different side lengths. You can find the side lengths(2,3,sqrt6) by plotting the triangle and using Pythagorean theorem. It is also visually clear that the triangle is obtuse if it is plotted.

Hope it helps <3

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Read 2 more answers

PLEASE HELP!! what is the equation for the parabolic function that goes through the points (-3, 67) (-1, 1) and has a stretch fa

barxatty [35]

Answer:

$f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}$

Step-by-step explanation:

So, we need to find the equation of a parabolic function that goes through the points (-3,67) and (-1,1) and has a stretch factor of 9.

In other words, we want to find a quadratic with a vertical stretch of 9 that goes through the points (-3,67) and (-1,1).

To do so, we first need to write some equations. Let's use the vertex form of the quadratic equation. The vertex form is:

$f(x)=a(x-h)^2+k$

Where a is the leading coefficient and (h,k) is the vertex.

Since a is the leading coefficient, it's also our stretch factor. Thus, let a equal 9.

Also, we have two points. We can interpret them as functions. In other words, (-3,67) means that f(-3) equals 67 and (-1,1) means that f(-1) equals 1. Write the two equations:

$f(x)=a(x-h)^2+k\\f(-3)=67=9((-3)-h)^2+k$

And:

$f(x)=a(x-h)^2+k\\f(-1)=1=9((-1)-h)^2+k$

Now, we essentially have a system of equations. Thus, to find the original equation, we just need to solve for the vertex. To do so, first isolate the k term in the second equation:

$1=9(-1-h)^2+k\\k=1-9(-1-h)^2$