Answer:
m= -90 is your answer
Step-by-step explanation:
For future reference, you should try using Symbolab, it works really well and I use it ALL the time!
Let the number of marbles be M,
then,
M=6a+4 (when shared among 6 students)
M=7b+4 (when shared among 7 students)
M=8a+4 (when shared among 8 students)
thus
M-4=6a
M-4=7b
M-4=8c
That is M-4 is the smallest number which is a multiple of 6, 7 and 8
Thus we need to find the LCM(6, 7, 8)
LCM(6, 7, 8)=LCM(2*3, 7, 2*2*2) = 2*2*2*3*7=8*21=168
The smallest M-4 is 168,
so the smallest M is 168+4=172
Answer: 172
Answer:
It can be done using poisson distribution.
λ = 30 calls/hr = 1.5 calls/3min
Now P(X=x)=e−λ.λxx!
So P(X=0)=e−1.5
Step-by-step explanation:
Answer:
Take whatever information you want from this but I don't think you'll need everything I'm gonna say.
Step-by-step explanation:
Both graphs have the same shape and open in the same direction. The only difference is that g(x) is translated down 2 units.
(I don't think you need this but) One more difference is that g(x) will have two x intercepts while x^2 will only have one point touching the x axis.
tan²(<em>x</em>) - sin²(<em>x</em>) = sin²(<em>x</em>)/cos²(<em>x</em>) - sin²(<em>x</em>)
… = sin²(<em>x</em>) (1/cos²(<em>x</em>) - 1)
… = sin²(<em>x</em>) (sec²(<em>x</em>) - 1)
… = sin²(<em>x</em>) tan²(<em>x</em>)