Question

6. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this week. She must get from one side of the school to the other by hurrying down three different hallways. She runs down the first hallway, a distance of 35.0 m, at a speed of 3.50 m/s. The second hallway is filled with students, and she covers its 48.0 m length at an average speed of 1.20 m/s. The final hallway is empty, and Suzette sprints its 60.0 m length at a speed of 5.00 m/s.
a. Does Suzette make it to class on time or does she get detention for being late again?
b. Draw a distance vs. time graph of the situation. (Assume constant speeds for each hallway.)

Answer 1

Step-by-step explanation:

hope this helps you

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Answer 2

Answer:

Refer to the attachment for calculations.$\Huge {\uparrow}$

Hence Sujata is late by 2 seconds.

Graph:-

$\setlength{\unitlength}{2.5mm}\begin{picture}(10,10)\linethickness{0.45mm}\put(20,20){\vector(1,0){18}}\put(20,20){\vector(-1,0){18}}\put(20,20){\vector(0,1){18}}\put(20,20){\vector(0,-1){18}}\multiput(19.35,6)(0,2){15}{\line(1,0){1.3}}\multiput(6,19.35)(2,0){15}{\line(0,1){1.3}}\put(20,20){\circle*{1}}\qbezier(20,20)(25,21)(27,36)\qbezier(20,20)(15,22)(13,36)\end{picture}$