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den301095 [7]
2 years ago
12

Omg plz help its a late assignment

Computers and Technology
1 answer:
balu736 [363]2 years ago
6 0

Answer:

C it's the correct option for your answer!!

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A(n) ________ is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.
melomori [17]

A(n) access point is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.

<h3>What is an access point?</h3>

An access point is known to be a kind of device that makes a wireless local area network, or WLAN, and it is often done in an office or big  building.

Therefore, A(n) access point is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.

Learn more about access point from

brainly.com/question/14306861

#SPJ12

6 0
2 years ago
Define the method object inc_num_kids() for PersonInfo. inc_num_kids increments the member data num_kids.Sample output for the g
topjm [15]

Answer:

class PersonInfo:

   def __init__(self):

       self.num_kids = 0

   def inc_num_kids(self):

       self.num_kids += 1

person1 = PersonInfo()

print('Kids:', person1.num_kids)

person1.inc_num_kids()

print('New baby, kids now:', person1.num_kids)

Explanation:

Line 1 of the code, we define the class PersonInfo. Line 3 of the code is the function that will increment the member data num_kids.

4 0
3 years ago
What is the best java 3d modeler library?
LenaWriter [7]
I believe its "Thinking Universe"
5 0
3 years ago
Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr
drek231 [11]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

3 0
3 years ago
What are the hardware and software components of a computer​
DaniilM [7]

Answer:

I. Hardware components of a computer includes monitor, speaker, central processing unit, motherboard, hard-drive, joystick, mouse, keyboard, etc.

II. Software components of a computer includes operating system, registry keys, antivirus, media player, word processor, etc.

Explanation:

The hardware component of a computer can be defined as the physical parts or peripherals that enables it to work properly. Some examples of hardware components are monitor, speaker, central processing unit, motherboard, hard-drive, joystick, mouse, keyboard, etc.

A software component of a computer comprises of software application or program that are used by the computer to manage or control software application, computer hardware and user processes. Some examples of software components are operating system, registry keys, antivirus, media player, word processor, etc.

In conclusion, the hardware components of a computer are the physical parts that can be seen and touched while the software components cannot be touched but rather are installed as a program.

8 0
3 years ago
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