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3 years ago

No links please ASAP!!! Find the slope of the line that passes through (5,3) and (4,2).

Mathematics

1 answer:

hodyreva [135]3 years ago

5 0

Answer:

Step-by-step explanation:

y2 - y1/ x2 - x1

3-2/ 5-4 = 1/1 = 1

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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I have no congruent sides. One of my angles has a measure of 100 degrees.

aliina [53]

The answer is a scalene triangle

5 0

3 years ago

What is the slope of a line that contains the points (2,-7) and (-1, -6)

Bogdan [553]

Answer:

Slope = - 1/3

Step-by-step explanation:

Y2-Y1 / X2 - X1

8 0

3 years ago

2. Victor Larson had fixed costs totaling $2,805.60 last year, not

Mashutka [201]

The depreciation of the car is $12,600.

The cost of the car per mile is $0.28

<h3>What is the depreciation of the car?</h3>

Depreciation is the decline in the value of an asset as a result of wear and tear.

Depreciation = cost of the asset - value of the asset now

$24,890 - $12,290 = $12600

Cost per mile = total cost / total mile

($2,805.60 + $1,870.40) / 16700 = $0.28

To learn more about depreciation, please check: brainly.com/question/25552427

5 0

2 years ago

. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0

3 years ago

Find the area of the following figure:

Sidana [21]

Answer: 15cm^2

Step-by-step explanation:

0.5*10*3=15

4 0

3 years ago

Read 2 more answers