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Digiron [165]
2 years ago
6

The following are the temperatures in °C for the first 8 days of January: -4.5, -1.5, 2, 3, -5, -2, -0.5, 2.5 What is the median

temperature for those 8 days?
Mathematics
1 answer:
Inga [223]2 years ago
3 0

Answer:

-1

Step-by-step explanation:

put numbers in order

-5 , -4.5 , -2 , -1.5 , -0.5 , 2 , 2.5 , 3

add two middle numbers up

- 1.5 + - 0.5 = -2

-2/2 = -1

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Answer: 10 < x < 60, or x is from 10 to 60

Step-by-step explanation: A domain of a graph consists of all of the input values shown on the x-axis while the range consists of all of the output values shown on the y-axis. Since the question asks to find the domain, you should look at the values of the graph from left to right. The domain includes all real numbers. Notice the black horizontal line on the graph and match up the beginning of it and the end of it with the values on the x-axis. The line begins at an x-value of 10 and ends at an x-value of 60; therefore, the domain (x-values) is from 10 to 60.

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Step-by-step explanation:

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3 years ago
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

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Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

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