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Dmitriy789 [7]
3 years ago
7

Factor 60-30w to identify the equivalent expressions

Mathematics
1 answer:
Mila [183]3 years ago
5 0

Answer:

30(2-w)

Step-by-step explanation:

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klasskru [66]

it is a linear equation

 if you take the negative of x and subtract 1 you get Y

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3 years ago
The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions
Mkey [24]

Answer:

Width = 18 inches

Length = 59 inches

Step-by-step explanation:

The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions

Perimeter of a rectangle = 2L + 2W

The length of a rectangle is five more than triple the width.

L = Length = 5 + 3W

W = Width

If the perimeter is 154 inches, what are the dimensions

Hence,

154 = 2L + 2W

154 = 2(5 + 3W ) + 2W

154 = 10 + 6W + 2W

Collect like terms

154 - 10 = 8W

144 = 8W

W = 144/8

W = 18 inches

Length = 5 + 3W

Length = 5 + 3(18)

Length = 5 + 54

Length = 59 inches

8 0
2 years ago
Simplify the following expression: 3m-5n+6m-8n
vichka [17]

3m - 5n + 6m - 8n \\ 3m + 6m - 5n - 8n \\ 9 m- 13n

5 0
2 years ago
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Vladimir [108]

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4 0
3 years ago
A ceiling light has a cross-section in the shape of a parabola. The parabola is 24 cm wide and 9 cm deep. The lightbulb is locat
Sedbober [7]

Answer:

  4 cm

Step-by-step explanation:

The equation of a parabola with its vertex at the origin can be written as ...

  y = 1/(4p)x^2

The problem statement tells us that one point on the parabola is (x, y) = (12, 9). We can put these values into the equation and solve for p, the distance from the focus to the vertex.

  9 = 1/(4p)(12^2)

  9×4/144 = 1/p = 1/4 . . . . . . . . multiply by the inverse of the coefficient of 1/p

Then p = 4, and the bulb is 4 cm from the vertex.

4 0
3 years ago
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