The diameters intersect at the center of the circle
m<BKD = 100
<AKC is vertical to <BKD, so m<AKC = 100
An arc has the same measure as its central angle,
so m(arc)AC = 100

5 0

3 years ago

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To complete one round of a jogging track, Samantha took 1.52 minutes. Which expression below represents the time taken by Samant

Inessa05 [86]

B i think because the .50+.2 make the .52 part

4 0

3 years ago

On a test with a population mean of 75 and standard deviation equal to 16, if the scores are normally distributed, what percenta

sashaice [31]

Answer:

Percentage of scores that fall between 70 and 80 = 24.34%

Step-by-step explanation:

We are given a test with a population mean of 75 and standard deviation equal to 16.

Let X = Percentage of scores

Since, X ~ N( $\mu,\sigma^{2}$ )

The z probability is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1) where, $\mu$ = 75 and $\sigma$ = 16

So, P(70 < X < 80) = P(X < 80) - P(X <= 70)

P(X < 80) = P( $\frac{X-\mu}{\sigma}$ < $\frac{80-75}{16}$ ) = P(Z < 0.31) = 0.62172

P(X <= 70) = P( $\frac{X-\mu}{\sigma}$ < $\frac{70-75}{16}$ ) = P(Z < -0.31) = 1 - P(Z <= 0.31)

= 1 - 0.62172 = 0.37828

Therefore, P(70 < X < 80) = 0.62172 - 0.37828 = 0.24344 or 24.34%

6 0

3 years ago