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Jobisdone [24]
3 years ago
11

What could explain what happened when the time was equal to 120 minutes

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Lets split the given graph in three parts.

First part: 0 to 30 minutes

We can see between this period, 0 to 30 minutes, the distance from home keeps increasing. It means from 0 to 30 minutes, Eli is moving towards the library.

Second part: 30 to 120 minutes

between 30 to 120 minutes,the distance from home does not changes. It means during this period, Eli is at the library.

Third part : 120 minutes to 135 minutes

Between 120 to 135 minutes, the distance from home is decreasing.

It means Eli is returning home in that period.

It means, at 120minute, Eli started her bicycle , home from the library. Hence option (b)     :    Answer

Hope it will help :)

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Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

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3 years ago
Help Me plz!
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Answer:

3,465 in³

Step-by-step explanation:

V=LWH

V=21 x 11 x 15 (the height of the water)

V= 3465


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