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3 years ago

What is an expression that simplifies to x to the 24 power

Mathematics

1 answer:

vlada-n [284]3 years ago

6 0

Answer:

x⁹ * x⁸ * x⁷

Step-by-step explanation:

when numers with the same base are multiplied the exponents are added

x⁹ * x⁸ * x⁷

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What is the solution to the system of equations. 2x-y=7 y=2x+3

OLEGan [10]

To solve this, you can substitute the second equation into the first.

It becomes 2x-(2x+3)=7

Solve from here!

You get -3=7. Not possible. Therefore there is no solution to this system.

System is inconsistent. Hope this helps.

8 0

4 years ago

Which methods will determine 70% of 42?

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

Given

(3x + 7)(2x - 6)

Each term in the second factor is multiplied by each term in the first factor, that is

3x(2x - 6) + 7(2x - 6) ← distribute both parenthesis

= 6x² - 18x + 14x - 42 ← collect like terms

= 6x² - 4x - 42 → C

5 0

3 years ago

Read 2 more answers

Are 5/8 and 2/3 equivalent

Phoenix [80]

Answer:

False

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A line passes through the point(-4,-6) and has a slope of 1/2 What is the equation of the line?

alex41 [277]

Answer:

x-2y-8=0

Step-by-step explanation:

The equation of line is given by the relation

y-y1=m(x-x1)

where m is the slope

now, given x1=-4 and y1=-6 and the slope is 1/2.

substitute into the equation to get

y+6=1/2(x+4)

multiplying through with the L.C.M

which is 2

2(y+6)=1/2×2(x+4)

2y+12=x+4

making x the subject

x= 2y+8 hence the equation of the line is x-2y-8 =0

4 0

3 years ago

Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

6 0

3 years ago