Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
<span>i think you mean discriminant in part A
</span>
Δ=b^2-4ac=256-4*2*3=256-24=232
it is positive so it has two answers.
Part B
you can find Δ
Δ=b^2-4ac=9-4*9*(-2)=81
x1=-3+9/18=6/18=1/3
x2=-3-9/18=-12/18=-2/3
Answer:
They will have values in common
Step-by-step explanation: I GUESSED
Answer:
You can't answer this properly without more data.
