All categories

3 years ago

Urgent!!!

Mathematics

1 answer:

Kitty [74]3 years ago

5 0

Answer:

its B) 3<x<7 bcs if u can see u have to start from the y xs and go up 3 and over 7

You might be interested in

According to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches; with a standard

Alecsey [184]

Answer:

Probability that the mean daily precipitation will be 0.09 inches or less for a random sample of 40 November days is 0.103.

Step-by-step explanation:

We are given that according to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches; with a standard deviation of 0.05 inches.

A random sample of 40 November days is taken(taken over many years).

Let $\bar X$ = sample mean daily precipitation

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 0.10 inches

$\sigma$ = population standard deviation = 0.05 inches

n = sample of days = 40

Now, the probability that the mean daily precipitation will be 0.09 inches or less is given by = P( $\bar X$ $\leq$ 0.09 inches)

P( $\bar X$ $\leq$ 0.09 inches) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{0.09-0.10}{\frac{0.05}{\sqrt{40} } }$ ) = P(Z $\leq$ -1.265) = 1 - P(Z < 1.265)

= 1 - 0.8971 = 0.1029

The above probability is calculated by looking at the value of x = 1.265 from the z table which will lie between x = 1.26 and x = 1.27 which has an area of 0.89617 and 0.89796 respectively.

Hence, the probability that the mean daily precipitation will be 0.09 inches or less for a random sample of 40 November days is 0.103.

8 0

3 years ago

-3/8 divided by -2/3

Dimas [21]

Answer is 1/16.

Please mark brainiest :)

3 0

3 years ago

Read 2 more answers

For each recursively-defined sequence below, write the first few term. Then use the terms to write an explicit equation.

Roman55 [17]

Answer:

Step-by-step explanation:

a_1 = 15

a_2 = a_1 - 3

a_2 = 15 - 3

a_2 = 12

a_3 = a_2 - 3

a_3 = 12 - 3

a_3 = 9

a_4 = a_3 - 3

a_4 = 9 - 3

a_4 = 6

a_5 = 3

a_6 = 0 I'm leaving these last two to expand

a_n = a1 - (n - 1)*d

a_n = 15 - (n - 1)*3

a_n = 15 - 3n + 3

a_n = 18 - 3n

Example

a_6 = 18 - 3*6

a_6 = 0

Problem B

t(1) = 108

t(1 + 1) = 1/3 * 108

t(2) = 36

t(3) = 1/3 * t2

t(3) = 1/3 * 36

t(3) = 12

t(4) =1/3 (t(3))

t(4) = 1/3 * 12

t(4) = 4

t(5) = t4 / 3

t(5) = 4 / 3

t(5) = 1.3333333

So the explicit definition is

t(n) = 108 (1/3)^(n - 1) You could simplify this a little bit by realizing that 108 is made of three 3s.

t(n) = 4 * 3^3 * (1/3)^(n - 1)

t(n) = 4 * (1/3) ^ (n - 4)

Example

t(5) = 108 (1/3)^4

t(5) = 108(1/81)

t(5) = 1.3333333

And using the simplified formula, you get.

t(5) = 4 * (1/3)^1

t(5) = 1.333333 which is the same thing as the original result.

7 0

3 years ago

Read 2 more answers

PLEASE HELP. What is the value of X in the photo below? (please show work)

Tom [10]

Value of x is 5. I remember doing this last year..

35a+45b=80

then we would do 99-80, and that gives us the value of c, 19

5 0

3 years ago

Which theorem could kari use to show the measure of angle qml is supplementary to the measure of angle snk? (1 point)?

shepuryov [24]

Kari used the theorem of "Same-Side Interior Angles Theorem". The Same -Side Interior Angles Theorem states that, when two lines that are parallel are intersected by a transversal line, the same-side interior angles that are formed are supplementary, or add up to 180 degrees.

5 0

3 years ago