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OverLord2011 [107]
3 years ago
12

One number is 3 times a first number, a third number is 100 more than the first number. If the sum of the three number is 245. F

ind the numbers
Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

The numbers are 29, 87 and 129.

To find these, you have to first assume that the first number is equal to x. After that we can write statements for the other numbers based on that. The second number is three times the first, which makes it 3x. The third is 100 more than the first, which makes it x + 100. Now we can add these 3 together and set equal to 245 to solve.

x + 3x + x + 100 = 245 ------> Combine like terms

5x + 100 = 245 -----> Subtract 100 from both sides

5x = 145 -----> Divide both sides by 5

x = 29

You can then plug the 29 into each of the other equations to find the remaining numbers.

3x = 87

x + 100 = 129

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Solve using a system of two equations in two unknowns.
vladimir1956 [14]

Hello!

To solve this, first write two equations. We are given two facts about the situation, so we can write the equations accordingly.

Say the length of the rectangle is l, and the width is w.

<u>The length of a rectangle is 9 inches more than twice its width:</u> 2w + 9 = l, as you're adding 9 to two times the width.

<u>The perimeter of the rectangle is 48 inches:</u> The equation for perimeter is 2l + 2w, so we can just use that in this case to make the equation - 2l + 2w = 48

Now, set up the system of equations.

\left \{ {{2w + 9 = l} \atop {2l + 2w = 48}} \right.

Now, we can already use substitution to solve. We get from one of the equations that l = 2w + 9, so we can substitute 2w + 9 for l in the other equation, and then solve for w.

2l + 2w = 48

2 (2w + 9) + 2w = 48

4w + 18 + 2w = 48

6w = 30

w = 5

We know one of our variables now. Now, all that's left to do is substitute 5 for w in one of the original equations to solve for l.

2w + 9 = l

2 (5) + 9 = l

10 + 9 = l

19 = l

Therefore, we now have our dimensions. The length of the rectangle is 19 inches, and the width is 5.

Hope this helps!

4 0
3 years ago
What is the outlier for the data set?<br><br> A. There is none<br> B. 5<br> C. 10<br> D. 9
zmey [24]
The outlier in the data set is 5
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3 years ago
Which of the following is the absolute value parent function
Keith_Richards [23]
The absolute parent function is |X|.

It is Choice B. because all the other choices are transformations of the parent function except for Choice D. which is just a line on the x-axis. 
4 0
4 years ago
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The time a randomly selected individual waits for an elevator in an office building has a uniform distribution with a mean of 0.
Amiraneli [1.4K]

Answer:

The mean of the sampling distribution of means for SRS of size 50 is \mu = 0.5 and the standard deviation is s = 0.0409

By the Central Limit Theorem, since we have of sample of 50, which is larger than 30, it does not matter that the underlying population distribution is not normal.

0% probability a sample of 50 people will wait longer than 45 seconds for an elevator.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size, of at least 30, can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.5, \sigma = 0.289

What are the mean and standard deviation of the sampling distribution of means for SRS of size 50?

By the Central Limit Theorem

\mu = 0.5, s = \frac{0.289}{\sqrt{50}} = 0.0409

The mean of the sampling distribution of means for SRS of size 50 is \mu = 0.5 and the standard deviation is s = 0.0409

Does it matter that the underlying population distribution is not normal?

By the Central Limit Theorem, since we have of sample of 50, which is larger than 30, it does not matter that the underlying population distribution is not normal.

What is the probability a sample of 50 people will wait longer than 45 seconds for an elevator?

We have to use 45 seconds as minutes, since the mean and the standard deviation are in minutes.

Each minute has 60 seconds.

So 45 seconds is 45/60 = 0.75 min.

This probability is 1 subtracted by the pvalue of Z when X = 0.75. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.75 - 0.5}{0.0409}

Z = 6.11

Z = 6.11 has a pvalue of 1

1-1 = 0

0% probability a sample of 50 people will wait longer than 45 seconds for an elevator.

8 0
3 years ago
At 6:00 p.m. the temperature was –5°F outside. By midnight the temperature had dropped 12 degrees. What was the temperature at m
USPshnik [31]
-5 - 12 = -17

Starts at -5 degrees, then it drops another 12, so you subtract 12 from -5.
6 0
3 years ago
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