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Natali5045456 [20]
3 years ago
7

$45.50 MP3 player; 7% tax

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

$ 48.69

Step-by-step explanation:

Hope this helps give me some stars and a Thank you if its correct!

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Value of sec (-17pi/6)
Ymorist [56]
Hello here is a solution :

5 0
3 years ago
Which of the following is the cube root of 125 ?
atroni [7]

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3

Step-by-step explanation:

3 0
3 years ago
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A force of $20$ newtons will stretch a spring $5$ centimeters. What is the total number of centimeters that a force of $60$ newt
Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Hooke's Law applies here, which is a linear relationship. It would be easier to solve this using proportions with N of force on the top and the amount of stretch in cm on the bottom. Set up with our unknown, the number of cm:

\frac{N}{cm}:\frac{20}{5}=\frac{60}{x} and cross multiply:

20x = 300 so

x = 15 cm

6 0
3 years ago
During a 20 kilometer hike, Deana consumed 334 quarts of water. What was Deana's average water consumption in quarts per kilomet
boyakko [2]

Answer:

  • 16.7 quarts/km

Step-by-step explanation:

  • Distance = 20 km
  • Water consumed = 334 quarts

<u>Water consumption rate is:</u>

  • 334 quarts / 20 km = 16.7 quarts/km
8 0
3 years ago
The sum of four consecutive terms of an arithmetic progression is 32 and the ratio of product of the first and the last term to
OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

Explanation:

Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

It is given that the sum of four consecutive terms is 32.

Thus, adding all the four consecutive terms, we have,

\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0
3 years ago
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