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3 years ago

10

First to get it correct will get brainleist! :) ASAP

2 answers:

vaieri [72.5K]3 years ago

5 0

Are the ones on the side the answers ??

nlexa [21]3 years ago

4 0

The answer to this question is B. U’(0,-1)

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The sum of the digits of a two-digit number is 14. If the number formed by reversing the digits is less than the original number

HACTEHA [7]

Answer:

86

Step-by-step explanation:

1. a+b=14 ⇒ a= 14-b

2. 10a+b=18+10b+a ⇒ a= 2+b

comparing 1 and 2:

14-b= 2+b ⇒ 2b= 12 ⇒ b= 6

a= 14-b= 8

number = 86

reversed number = 68

3 0

3 years ago

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

What is the perimeter of the figure?

Likurg_2 [28]

All the sides add like a rectangle with two sides measuring 4 and two measuring 2 so you would add 4+4+2+2=12

4 0

4 years ago

Read 2 more answers

An amateur radio operator erects a 75-foot vertical tower for an antenna. A 117 guy wire is pulled from the top of the tower dia

vitfil [10]

Answer:

α=39.80°

Step-by-step explanation:

applying the law of sin and cos, we have:

$sin\alpha =\frac{75}{117}=0.6410\\\alpha =acs(0.64)= 39.79$

and to the nearest tenth of a degree

α=39.80°

3 0

3 years ago

Jane borrowed a total of 23000 from 2 different banks to start a Business One bank charge the equivalent of 5% simple interest a

krek1111 [17]

gjbskbgkjfbgsbfgjbkfsbgksfbgsfkjbg

4 0

4 years ago