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KatRina [158]
2 years ago
11

Five packages A, B, C, D, and E are shipped out. The values below represent the

Mathematics
1 answer:
Mariulka [41]2 years ago
4 0

If it's likely to happen, but it's not a certainty, then it has a high chance of happening. Pick P(D).

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Find the value of the combination. 10C0
Andrej [43]

Answer:The formula for a combination of choosing r unique ways from n possibilities is:

nCr  =   n!

  r!(n - r)!

where n is the number of items and r is the unique arrangements.

Plugging in our numbers of n = 10 and r = 0, we get

10C0  =   10!

  0!(10 - 0)!

10C0  =   3,628,800

  3,628,800

8 0
2 years ago
Read 2 more answers
A baseball league forms using a total of 12 coaches, 78 players
Ipatiy [6.2K]
And what else is in the problem I do not get what the problem is
4 0
3 years ago
Ik what it is just helping out others 1+1
antiseptic1488 [7]

The question is asking what will we get if we add 1+1.

Let us use an example to understand this.

Example:

Suppose Amy has 1 ice cream and her brother Ruth has also got one ice cream.

Now if they both finished their ice creams, how many total ice creams were finished.

So we see that 1 and 1 add up to give two ice creams and so two ice creams are finished by them both.

Applying this to our question adding 1 and 1 gives us 2.

Answer : 1+1 =2

3 0
3 years ago
Read 2 more answers
Classify the statements based on whether they are represented by +3 or -3.
adell [148]

Answer:

If you deposit money, your bank account shows it as +3

3 degrees below zero = - 3 o F which is darn cold.

3 floors below ground level = - 3 floors below ground level

3 feet above sea level = +3 feet

3 degrees about 0 = + 3

3 dollars lost = -3 dollars.

Step-by-step explanation:

7 0
3 years ago
(6x10^2)/(3x10-5) help what is this in standard form?
Tasya [4]

<u>Answer: </u>

The standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

<u>Solution: </u>

Given that \frac{6 \times 10^{2}}{3 \times 10^{-5}} ---- eqn 1

To write\frac{6 \times 10^{2}}{3 \times 10^{-5}} in standard form,

We know that \bold{\frac{1}{a^{-m}} = a^{m}} .So \frac{1}{10^{-5}}  becomes 10^{5}.

Now eqn 1 becomes,

= \frac{6 \times 10^{2}}{3} \times 10^{5} ----- eqn 2

We know that \bold{a^{m} \times a^{n}=a^{m+n}}, so 10^{2} \times 10^{5} = 10^{7}

Now eqn 2 becomes,

= \frac{6}{3} \times 10^{7}

= 2 \times 10^{7} ---- eqn 3

Expanding 10^{7}:  

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

Now eqn 3 becomes,

= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

= 20,00,0000  

Hence the standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

6 0
3 years ago
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