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insens350 [35]
3 years ago
13

Find the length of AB when A(-4,1) and B(3,-1). Round to the nearest tenth (one decimal place) if necessary.

Mathematics
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

7.3 units is the answer rounded

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9.03 divided by 899.8 is closest to a.0.01

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What is the value of the expression below when w=2
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26

Step-by-step explanation:

8 * 2 + 10 = 26

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The number of basic trigonometric ratios is....<br><br> A.3<br> B.4<br> C.5<br> D.6
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There are three basic trigonometric ratios: sine , cosine , and tangent .

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Compute the discriminant D(x,y)D(x,y) of the function. f(x,y)=x3+y4−6x−2y2+3 f(x,y)=x3+y4−6x−2y2+3 (Express numbers in exact for
Igoryamba

Answer:

Point                Critical point

Q (2,0)                 local minimum

R (-2,1)                 Saddle

S (2,-1)                  local maximum

T ( -2,-1)                Saddle

O ( -2,0)                Saddle

Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE

f(x,y) = x³ +y⁴ - 6x -2y² +3

df/dx = f´(x) = 3x² -6x

df/dxdx = f´´(xx) = 6x

df/dy = f´(y) = -4y

df/dydy = 4

df/dydx = df/dxdy = 0

df/dydy = f´´(yy)

D = [ df/dxdx *df/dydy] - [df/dydx]²

D = (6x)*4 - 0

D = 6*2*4     D > 0 and the second derivative on x is  6*2 = 12

so  D > 0 and df/dxdx >0  there is a local minimum in P

Q(2,1)

D = (6*2)*4  D>0  and second derivative on x is 6*2

The same condition there is a minimum in Q

R ( -2,1)

D = 6*(-2)*4 = -48  D< 0 there is a saddle point in R

S (2,-1)

D = 6*2*4 = 48  D > 0 and  df/dxdx = 6*-1  = -6

There is a maximum in S

T ( -2,-1)

D = 6*(-2)*(4) = -48  D<0 there is a saddle point in T

O ( -2,0)

D = 6*(-2)*4 = -48 D<0  there is a saddle point in O

5 0
3 years ago
0.009,0.8,0.05,1.0 in ascending order
Andrew [12]
0.009, 0.05, 0.8, 1.0
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4 years ago
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