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2 years ago

A rectangular flower garden in Samantha's backyard has 260 feet around its edge. The width of the garden is 60 feet.

Mathematics

1 answer:

OlgaM077 [116]2 years ago

4 0

Answer:

100 - 20 = 80 Length Of the Garden

Step-by-step explanation:

So You Can do 20 Ft Minus 100 Because 100 is the Total so Heres a Graph To Show You

Total= 100 Ft

Width= 20

Length=?

Total - Width = Length

100 - 20 = 80 Length Of the Garden

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The graph is shown for the equation y = –x + 4.

ivann1987 [24]

Answer:

Option C. $y=-\frac{1}{2}(2x-8)$

Step-by-step explanation:

we know that

If a system of two linear equations has an infinite number of solutions, then both equations must be identical

The given equation is

$y=-x+4$

Verify each case

Option A. we have

$y=-4(x+1)$

apply distributive property

$y=-4x-4$

Compare with the given equation

$-x+4 \neq -4x-4$

Option B. we have

$y=-(x+4)$

remove the parenthesis

$y=-x-4$

Compare with the given equation

$-x+4 \neq -x-4$

Option C. we have

$y=-\frac{1}{2}(2x-8)$

apply distributive property

$y=-x+4$

Compare with the given equation

$-x+4=-x+4$

therefore

This equation with the given equation form a system that has an infinite number of solutions

Option D. we have

$y=x+4$

Compare with the given equation

$-x+4 \neq x+4$

7 0

3 years ago

east side middle school has 1,500 students. Thirty-two percent of them are in sixth grade. How many sixth grade students are the

77julia77 [94]

480 6th grade students
:)

3 0

3 years ago

Odd numbers greater than -40 but less than -28

AURORKA [14]

-39, -37, -35, -33, -31, -29. Odd numbers are the same just backwards ;)

7 0

3 years ago

Read 2 more answers

Solve. m - 15 = 20 m =

Fittoniya [83]

$\text{Hello There!}$

$\text{We are going to need to isolate the variable}$

$m - 15 = 20$

$\text{Add 15 to both sides.}$

$\text{We do this because we need to perform inverse operations to find}$ $\text{the value of the variable.}$

$m - 15 + 15 = 20 + 15 = 35$

$\fbox{Therefore, your answer is going to be 35.}$

$\rule{300}{1.5}$

7 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

2 years ago