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valentinak56 [21]
3 years ago
13

Which of the polygons are similar to polygon a ​

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

poly gon B is similar and polygon E is congruent

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ruslelena [56]

Answer: it’s C

Step-by-step explanation:

7 0
3 years ago
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Find d using a trigonometric ratio
Radda [10]

Answer: 38 is your answer hope this helped

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Step-by-step explanation:

4 0
3 years ago
Match each equation to its factorized version and solution. 24x – 6x2 = 0 2x(x 3) = 0 solution: x = 0, x = -3 14x – 7x2 = 0 6x(4
Archy [21]

So, The correct match of these quadratic equations are
Equation A has a solution x = 3 and x = 0.

Equation B has a solution x = 2 and x = 4.

Equation C has a solution x = -3 and x = 0.

Equation D has a solution x = 4 and x = 0.

According to the equation

we have given that the some equation with there values of the x and we have to find and match the correct statement with the given values of x.

So, For this purpose, we know that the

The given quadratic equations are:

A. 24x – 6x^2 = 0 and 2x(3x) = 0 with solution x = 0, x = -3

B. 14x – 7x^2 = 0 and 6x(4 – x) = 0 with solution x = 0, x = 4

C. 2x^2+ 6x = 0 and x(4 – x) = 0 with solution x = 0, x = 4

D. 4x – x^2 = 0 and 7x(2 – x) = 0 with solution x = 0, x = 2

And now we solve it

So,

Take A.

24x – 6x^2 = 0 and 2x(3x) = 0

6x(3 -x) = 0 And 6x^2 = 0

here x = 3 and x = 0.

And

Take B.

14x – 7x^2 = 0 and 6x(4 – x) = 0

7x(2 -x) = 0 And 6x(4 – x)= 0

here x = 2 and x = 4.

And

Take C.

2x^2+ 6x = 0 and x(4 – x) = 0

2x(x +3) = 0 And x(4 – x)= 0

here x = -3 and x = 0.

And

Take D.

4x – x^2 = 0 and 7x(2 – x) = 0

x(4 -x) = 0 And 7x(2 – x)= 0

here x = 4 and x = 0.

So, The correct match of these quadratic equations are
Equation A has a solution x = 3 and x = 0.

Equation B has a solution x = 2 and x = 4.

Equation C has a solution x = -3 and x = 0.

Equation D has a solution x = 4 and x = 0.

Learn more about quadratic equations here

brainly.com/question/1214333

#SPJ4

7 0
2 years ago
A compound inequality to represent all of the numbers between -4 and 6.
andriy [413]
Hello : 
<span>A compound inequality to represent all of the numbers between -4 and 6 is : 
- 4 </span>< x <span>< 6
</span>x <span>> - 4   and  </span>x < 6

5 0
4 years ago
Julia rides her horse 18 km with a constant speed of 6km/hr and another 24 km with a constant speed of 12 km/hr. What is her ave
nlexa [21]

Answer:

8.4 km/hr.

Step-by-step explanation:

We have been given that Julia rides her horse 18 km with a constant speed of 6 km/hr.

Let us find the time taken by Julia to cover a distance of 18 km.

\text{Time}=\frac{\text{Distance}}{\text{Speed}}

\text{Time taken to cover 18 km}=\frac{18\text{ km}}{\frac{6\text{km}}{\text{hour}}}

\text{Time taken to cover 18 km}=\frac{18\text{ km}}{6}\times\frac{\text{hour}}{\text{km}}

\text{Time taken to cover 18 km}=\frac{18}{6}\times\text{hour}

\text{Time taken to cover 18 km}=3\text{ hour}

We are also told that she rides another 24 km with a constant speed of 12 km/hr.

Let us find the time taken by Julia to cover a distance of 24 km.

\text{Time taken to cover 24 km}=\frac{24\text{ km}}{\frac{12\text{km}}{\text{hour}}}

\text{Time taken to cover 24 km}=\frac{24\text{ km}}{12}\times\frac{\text{hour}}{\text{km}}

\text{Time taken to cover 24 km}=\frac{24}{12}\times\text{hour}

\text{Time taken to cover 24 km}=2\text{ hour}

Since we know that \text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}.

Upon substituting our values in above formula we will get,

\text{Julia's average speed}=\frac{18\text{ km}+24\text{ km}+}{3\text{ hour}+2\text{ hour}}

\text{Julia's average speed}=\frac{42\text{ km}}{5\text{ hour}}

\text{Julia's average speed}=\frac{8.4\text{ km}}{\text{ hour}}

Therefore, Julia's average speed is 8.4 km per hour.


5 0
4 years ago
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