Answer:
The second and third
Step-by-step explanation:
Answer:
<h2><u><em>
6. </em></u></h2><h2><u><em>
a. 11 and 2/3 yds. squared</em></u></h2><h2 /><h2><u><em>
b. Yes, the volume of the shed is 11 and 1/3 yards squared and what she's trying to put into it is only 10 yards squared, if put in properly, it will be able to fit.</em></u></h2><h2 /><h2><u><em>
7. 1,110 in. squared</em></u></h2>
Step-by-step explanation:
6.
a.
(10/3)*(14/9)*(9/4)
= 11 2/3
b.
Yes, because the volume of the shed is about 11.67 yards long, the 10 yards of wood will fit in the shed.
7.
For this one, we have to break it into two pieces.
(I made them into a small box and and big box)
The measurements of the small box are 7*5*6.
The measurements of the big box are 20*5*9.
Using this information, we can make the following equation and solve it quickly.
(7*5*6) + (20*5*9)
(210) + (900)
1,110
Thus, the volume of this box is 1,110 in. ^2
Answer: D
Step-by-step explanation:
g(x)=f(x-2)=8(x-2)+1=8x-16+1=8x-15
Answer:
The correct option is;
Increasing one fifth unit/sec
Step-by-step explanation:
The equation that gives the curve of the particle of the particle is y = 5·x² - 1
The rate of decrease of the y value dy/dt = 2 units per second
We have;
dy/dx = dy/dt × dt/dx
dy/dx = 10·x
dy/dt = 2 units/sec
dt/dx = (dy/dx)/(dy/dt)
dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)
When x = 1
dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec
dx/dt = 1/5 unit/sec
Therefore, x is increasing one fifth unit/sec.
Answer: 5km per hour
Step-by-step explanation:
You'd do 20/number of hours so you get 1 hour and you'll get his walking speed