4 years ago

28 students take a test, 22 pass. What percentage passed the test?

Mathematics

2 answers:

Sergeu [11.5K]4 years ago

5 0

78.57% of the students passed

trapecia [35]4 years ago

5 0

22/28=.7857 x 100= 78.57 % passes

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Answer:

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Step-by-step explanation:

Given

$8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3$

Required

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We have:

$8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3$

Collect like terms (in decreasing degrees of m)

$- 2m^6 - 4m^6 - mn^5- m^3n^3 - 4m^3n^3+ 5m^2n^4 + 9m^2n^4 + 8mn^5 + n^6$

$-6m^6 - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5 + n^6$

So:

$8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6 - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5 + n^6$

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