All categories

3 years ago

How can u find the number of inches in one mile

Mathematics

2 answers:

pav-90 [236]3 years ago

7 0

Answer:

63360

Step-by-step explanation:

==> 5280 ft = x inch. ==> x = 12*5280 = 63360 inch. Then, there are 63,360 inches in one mile.

kow [346]3 years ago

4 0

Answer:

There are 63,360 inches in one mile.

Step-by-step explanation:

We multiply by the conversion factor:

1 mile (5280 feet/1 mile)(12 inches/1 foot)= 63,360 inches per mile.

You might be interested in

The population of camden, New Jersey has been decreasing by 0.12% a year on average. If this trend continues, and the population

Talja [164]

By the trend that is being given above, the population of New Jersey will only be 99.88% of the population from the previous year. It may be calculated through the following equation,
P(n) = P(0) x (1 - r)^n
Substituting the values from the given above,
P(n) = 79,318 x (0.9988)^(2015 - 2006)
= 78465.47
Thus, the population will approximately be 78,466.

4 0

3 years ago

PLEASE HELP ME I WILL GIVE BRAINLIST

liq [111]

1)
= 24z^7

answer
A. 24z^7

2)
= 24 x^2y^9

answer
D. 24 x^2y^9

3)
=w^12z^18

answer
C. w^12z^18

4)
= 4x^6

answer
B. 4x^6

4 0

3 years ago

Help mathhhhhhhhhhhhhhh

defon

90°/right angle I believe

5 0

3 years ago

For the function g(x) = 3x -21, what is g(6)

marishachu [46]

Answer:

3·6 - 21

Step-by-step explanation:

just replace x with 6

3 0

3 years ago

Read 2 more answers

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

3 years ago