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xz_007 [3.2K]
3 years ago
5

Plzz help really fast

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0

Answer:

the answer is 32

Step-by-step explanation:

Kipish [7]3 years ago
4 0

Answer:

32

Step-by-step explanation:

Let's do it step by step:

-16(-5\frac{1}{2} \div 2\frac{3}{4}) = -16(\frac{-5\frac{1}{2}}{2\frac{3}{4}}) = -16(\frac{-\frac{11}{2}}{\frac{11}{4}}) = -16(-\frac{4}{2}) = -16\cdot(-2) = 32

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Y=99.99+23.75(x-1) as a Y=ax+b equation
Hatshy [7]

Answer:

y = 23.75x  + 76.24

Step-by-step explanation:

We want to rewrite

y = 99.99 + 23.75(x - 1)

in the form

y = ax + b

We expand to get:

y = 99.99 + 23.75x - 23.75

Regroup similar terms:

y = 23.75x - 23.75 + 99.99

Simplify:

y = 23.75x  + 76.24

This is now of the form

y = ax + b

where a=23.75 and b=76.24

6 0
4 years ago
Write in slope-intercept form an equation of the line that passes through the points (−1,12) and (1,2).
zzz [600]

Answer:

y=-5x+7

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

the points (−1,12) and (1,2)

substitute

m=\frac{2-12}{1+1}

m=\frac{-10}{2}

m=-5

step 2

we know that

The equation of the line in slope intercept form is equl to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=-5

point\ (1,2)

substitute in the linear equation and solve for b

2=-5(1)+b

b=2+5=7

therefore

y=-5x+7

4 0
3 years ago
Sami cut 6 and three fourth inches off a long roll of paper if the row 36 and one third inches long how long was the original ro
cestrela7 [59]

Answer:

43 1 ÷12

Step-by-step explanation:

The computation of the length of the original roll of papers is shown below:

36 1 ÷3 and 6 3 ÷ 4 together

Now convert the above fractions into a number

36 1 ÷ 3 = 109 ÷3

And,

6 3 ÷4 = 27 ÷ 4

Now add these two numbers i.e.

109 ÷3  + 27 ÷ 4

= 436 + 81 ÷ 12

= 517 ÷12

= 43 1 ÷12

6 0
3 years ago
Parker wants to ride his bicycle 34 miles this week. He has already ridden 10 miles. If he rides for 5 more days, how many miles
vazorg [7]

Answer: He rode 4.8 miles each day.

Variable: x = Constant distance distance traveledd each day.

Equation : 10+5x=34

Step-by-step explanation:

Total distance needs to travel = 34 miles

Distance already traveled = 10 miles

He will ride bicycle for 5  more days.

Let x = Constant distance distance traveledd each day.

Total distance = 10+5x

i.e.

10+5x=34\\\\\Rightarrow\ 5x=24\\\\\Rightarrow\ x=4.8

Hence, he rode 4.8 miles each day.

7 0
3 years ago
a wrestler is weighing in for their match this evening. their normal weight is 168 pounds, but that weight can vary by as much a
Natalija [7]

<em>Introduction </em>

<em>Wrestling is a wonderful activity with many advantages for the student-athlete. It is a sport that is highly </em>

<em>competitive, exciting and satisfying. It is a sport that provides for individual and team competition. It is - </em>

<em>and should be - fun. Unfortunately, the practice of losing weight by not eating, restricting fluid intake and </em>

<em>over-exercising reduces the sport's fun. This information is presented to help clear up misconceptions </em>

<em>regarding wrestling and weight loss. I also hope to give some guidance to those who desire to manage </em>

<em>their weight properly in preparation for and during the wrestling season. </em>

<em>History and Stigma </em>

<em>For too long, the wrestling community has unthinkingly accepted the myth that to be a good wrestler, you </em>

<em>must cut weight. The generally accepted thinking is something like this: if your natural weight is 135 </em>

<em>pounds, you may be a good wrestler at 135 pounds. But if you wrestle at 130 pounds, you'll be a better </em>

<em>wrestler. And if you can make it down to 125, you'll be a state champion. No facts support that widely held </em>

<em>view, yet wrestlers and parents subscribe to that faulty reasoning. Looking further back, many remember </em>

<em>the days that losing excessive weight was a specific practice and expectation among wrestlers. It was </em>

<em>supposed to teach sacrifice, commitment, and the idea of “No Pain, No Gain.” </em>

<em>Regardless of the current attitude of the majority of the wrestling community, the stigma that an unhealthy </em>

<em>loss of weight is a requirement of wrestling among outside observers sticks. The Virginia High School </em>

<em>League has followed national guidelines to establish rules that encourage healthy weight management </em>

<em>among wrestlers. </em>

<em>Current Regulations </em>

<em>Preseason weight certification is accomplished with three steps. The first is determining each wrestler’s </em>

<em>body fat percentage using skin fold calipers. Next, the wrestler completes a hydration test, to insure </em>

<em>against a dehydrated weight measurement, and the wrestler weighs in. The third step is the calculation of </em>

<em>the wrestler’s minimum wrestling weight based on 7% body fat for males and 12% for females. The </em>

<em>wrestler may not wrestle at a weight class below his minimum weight during the season. The wrestler is </em>

<em>also restricted from losing more then 1.5% body weight loss per week (official weigh-ins at certification, </em>

<em>matches, and tournaments are used for this calculation). A one-pound per month growth allowance is </em>

<em>provided to allow for the natural growth of this age group. The VHSL advises, and we have instituted, </em>

<em>daily weigh-ins before and after practice to monitor weight-loss and dehydration. </em>

<em>Additionally, the National Federation of State High School Associations has adopted several other rules to </em>

<em>guide coaches and wrestlers while managing their weight. Wrestlers are discouraged from wrestling at a </em>

<em>weight class more then one weight class above their certified weight. </em>

5 0
3 years ago
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