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xz_007 [3.2K]
3 years ago
5

Plzz help really fast

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0

Answer:

the answer is 32

Step-by-step explanation:

Kipish [7]3 years ago
4 0

Answer:

32

Step-by-step explanation:

Let's do it step by step:

-16(-5\frac{1}{2} \div 2\frac{3}{4}) = -16(\frac{-5\frac{1}{2}}{2\frac{3}{4}}) = -16(\frac{-\frac{11}{2}}{\frac{11}{4}}) = -16(-\frac{4}{2}) = -16\cdot(-2) = 32

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A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac
Nat2105 [25]

Answer:

<em><u>5</u></em><em><u> </u></em><em><u>points</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>8</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>po</u></em><em><u>ints</u></em><em><u> questions</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

Step-by-step explanation:

Let the number of 5 points questions be x and number of the 2 points questions be y !!

Given :- The paper has 38 problems

i.e,

number of 5 points Q + number of 2point Q = 38

=> x + y = 38

=> x = 38 - y .... ( i )

And , The test worth 100 pts :-

There must be x number of Questions which carry 5 points and there must y number of questions which carries 2 points ( as assume above )

so, 5x + 2y = 100 .... ( ii )

Putting value of the x in ( ii )

5 ( 38 - y ) + 2y = 100

190 - 5y + 2y = 100

- 3y = - 90

y = 30

Putting value of y in ( i )

x = 38 - y

x = 38 - 30

x = 8

So, the Number of 5points Question is

x = 8

and , the number of 2 points questions is y = 30 !!

4 0
4 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

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What is the domain of the function f(x)=√x?
Angelina_Jolie [31]

Answer:

Interval: [0,∞), solution: x≥0.

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Translate and simplify: the difference of -5 and -30
Andreas93 [3]

Answer:

they are the same . If u add (-5) + (-30) that will be equal to (-35)

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3 years ago
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Choose the inequality that represents the following graph
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Answer:

x < -1

Step-by-step explanation:

If it were greater than, then the arrow would be going towards the right instead of the left. If it were equal to as well, then the circle would be shaded.

5 0
3 years ago
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