Answer:
- see the attachment for a graph
- yes, you can carry 5 math books in one load (along with 0–2 science books)
Step-by-step explanation:
If x and y represent the number of math and science books you're carrying, respectively, then 3x and 4y represent their weights in pounds.
The total weight of the carry will be 3x+4y, and you want that to be at most 24 pounds. The expression modeling this is ...
... 3x +4y ≤ 24
A graph of this inequality is shown in the attachment. (We have added the constraints that the number of books not be negative.)
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5 math books will weigh 5·3 = 15 pounds, so will be within the limit you can carry.
Answer:A. The first one and second B.
Step-by-step explanation:i took the test i promise!
mark me as brainiest please!
The equation for the volume of a cylinder is pir^2h or 3.14*radius squared* height.
We can switch the equation around to find r^2=v/3.14*h
Now insert the known values.
R^2=1500/3.14*15
Solve
R^2=1500/47.1
R^2=31.8
R=5.6
Hope this helps!
The original number is 7 i think.
10(x^2) = 70x
10x^2 - 70x = 0
x^2 -7x =0
Δ= b^2 -4ac
where c doesnt exist=0
Δ= 49
-b ± √Δ /2a
7 ± √49 /2
7±7/2
x is either 14/2= 7
or 1/2, which doesnt work.
Lets see:
10(7^2) = 70•7
10•49 = 490
and that is right.
i hope my logic is correct.
You have to multiply the coefficient and add the exponents of the variables
