Answer:
p=122 q=80 r=80
Step-by-step explanation:
X+y+z=92
y=3x
z=2x-10
subsitute
x+3x+2x-10=92
6x-10=92
add 10 to both sdies
6x=102
divide by 6
x=17
subsitute
y=3x
y=3(17)
y=51
z=2x-10
z=2(17)-10
z=34-10
z=24
x=17
y=51
z=24
the numbers are 17,51,24
Answer:
5
Step-by-step explanation:
I hope this helps you out!
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
The second cylinder is taller correct?
8 in < 11 in
If the height is also larger, the base is most likely larger too.
Wouldn't the largest cylinder have a Larger surface area?
