Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Answer:
$550
Step-by-step explanation:
5.5 % = 0.055
10,000 x 0.055=550
3x+20=5x+12
-3x -3x
20= 2x +12
-12 -12
8=2x
Divide both sides by two
4=x
It will take four days (this is how to solve algebraically)
Find the mean, median, mode, and range of the data 10, 13, 7, 6, 9, 4, 6, 3, 5
elena-s [515]
Median is 6 range is 9 mode is 6 and mean is 7
The answer is D hope this helps
