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mihalych1998 [28]
2 years ago
11

Answer the question about the promissory note given.

Mathematics
1 answer:
myrzilka [38]2 years ago
8 0
That he is keeping track who he owes money to and when he has to do it
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A bracelet that normally sells for $30.00 is on sale for $25.50. What is the percent discount?
vekshin1

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15% off

Step-by-step explanation:

We know we paid $25.50 of the original $30. We can divide these two numbers \frac{25.5}{30}=0.85. This is means we paid 85% of the original price. The discount percentage is the remaining percentage from 85 to 100 which is 15. The pants were 15% off.

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Sergio comma Eduardo comma Maria comma Simone comma Ian comma Dawn comma Larry comma and Tyrone have all been invited to a dinne
ANTONII [103]

Answer:

a.

Step-by-step explanation:

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3 years ago
HELP HELP !!!! PLEASE I NEED HELP WITH THIS PROBLEM !!!
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This one is best done by elimination:

We need to start 4 meters away, so B is clearly wrong. 

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(D also doesn't start at 4, it's wrong for two reasons.)

Only C is left.

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Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly
kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0
2 years ago
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