<h2>
Answer with explanation:</h2>
Let p be the population proportion.
Then, Null hypothesis : 
Alternative hypothesis : 
Since the alternative hypothesis is right tailed , then the hypothesis test is a right tailed test.
Given : A random sample of 200 high school seniors from this city reveals that 162 plan to attend college.
i.e. n = 200 > 30 , so we use z-test (otherwise we use t-test.)
Test statistic for population proportion :
Thus, the z-value of the sample test-statistic = 0.72
P-value for right tailed test =
Since the p-value is greater than the significance level (0.05) , so we fail to reject the null hypothesis.
Hence, we conclude that we do not have sufficient evidence to support the claim that the percentage has increased from that of previous studies.
Answers:
a) 75ml/hr
b) 0ml left
Explanation:
a) 750ml - 450ml = 300ml (This is how much we know the bag drained within 4hrs)
300ml/4=75ml
so now we know the rate of drain is 75ml/hr
b) since rate is 75ml/hr:
75*6=450
450-450=0
Hence there will be no fluid left for the patient.
Answer:
y= -1/3+2
Step-by-step explanation:
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Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is: 
(∵V=lbh)
The maximum combined length and girth is 144.
Therefore, 
Substitute the value of y in volume of the box.
Substitute V'(x)=0.
Now apply second derivative test.
(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then 
Substituting value of x = 24 and y = 48 gives 27648.
Hence, the volume in such a package is 27648 in³
