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3 years ago

HELP HURRY NOW PLEASE!!

Mathematics

1 answer:

Neporo4naja [7]3 years ago

7 0

Answer:

interior angles will always be congruent and for the second question it would be x+ the measure of 6 =180 degrees

Step-by-step explanation:

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Fun center rents popcorn machines for &20 per hour. In addition to the hourly charge, there is a rental fee of $35. Is this

Gelneren [198K]

Answer:

No. It is not proportional.

4 0

3 years ago

?/8 = 3/? I am missing 2 numbers for a equivalent fraction problem it is a bit complicated.

lyudmila [28]

?/8 = 3/?
Multiplying both sides by 8, then “?” gives

8? * ?/8 = 8? * 3/?
?*? = 24
The number, then, is sqrt(24), or 2 sqrt(6), which is approximately 4.90.

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4 years ago

When blank an exponential expression to a blank you the exponents.

kherson [118]

Answer: i do not no

Step-by-step explanation:

6 0

3 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

3 years ago

An arrow is shot horizontally toward a target 20 m away. In traveling the first 5 m horizontally, the arrow falls 0.2 m. In trav

Elanso [62]

Answer:

The arrow will fall an additional 0.6 m.

Step-by-step explanation:

The height of the arrow can be calculated using the following kinematic equation of a falling object:

y = y0 + v0y · t + 1/2 · g · t²

Where:

y = height of the arrow at time "t"

y0 = initial height.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

t = time.

Since the arrow is shot horizontally, initially, it does not have a vertical velocity, so, v0y = 0.

If we place the origin of the frame of reference at the throwing point, y0 is also 0. Then:

y = 1/2 · g · t²

First, let´s calculate how much time it takes for the arrow to travel 5 m. It will be the time it takes the arrow to fall 0.2 m. Then, using the equation of height:

y = 1/2 · g · t²

-0.2 m = 1/2 · (-9.8 m/s²) · t² (notice that we consider the upward direction as positive and the origin of the frame of reference is at the throwing point).

-0.2 m / -(1/2 · 9.8 m/s²) = t²

t = 0.2 s

If we neglect air resistance, the horizontal velocity of the arrow will be constant because there is no force acting in the horizontal direction on the arrow. Then, the arrow will travel the next 5 m in another 0.2 s. Then, let´s find the height of the arrow at t = 0.4 s.

y = 1/2 · g · t²

Instead of t = 0.4 s I will use t = 2 · √(-0.2 m / -(1/2 · 9.8 m/s²)) (this expression was obtained above) to avoid error because of rounding:

y = 1/2 · (-9.8² m/s) · (2 · √(-0.2 m / -(1/2 · 9.8 m/s²)))²

y = -0.8 m

The height of the arrow when it travels another 5 m will be -0.8 m (0.8 m below the throwing point). It means that the arrow will fall an additional 0.6 m.

6 0

4 years ago