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2 years ago

(0, 2) (3, 8) write an equation in slope intercept form

Mathematics

1 answer:

jolli1 [7]2 years ago

7 0

Hello there , this is the anwser :)

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Find 0.01 more than 9.154

sp2606 [1]

Answer:

Hey!

Your answer is 9.164!!

Step-by-step explanation:

Adding 0.01 means just adding 1 to THE DIGIT IN THE HUNDRETH PLACE...2 SPACES RIGHT OF DECIMAL POINT!

5+1=6

SUB IN:

9.164

5 0

3 years ago

can someone help me solve this problem? math problem: stephanie earned $85 in 4 hours of work, she wants to buy a new computer f

gladu [14]

I’m not sure man, but yeah

3 0

3 years ago

you rent an apartment that costs $1600 per month during the first year ,but the rent is set to go up 11.5% per year.what would b

RoseWind [281]

Answer:

$4,750.

Step-by-step explanation:

To determine the rental value of the apartment in the tenth year, knowing that it is worth 1,600 during the first year but that it will be adjusted annually to 11.5%, the following calculation must be made:

X = 1,600 x (1 + 0.115) ^ 10

X = 4,751.91

Thus, at ten years, rounded to the nearest tenth, the rental value will be $ 4,750.

7 0

2 years ago

Read 2 more answers

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .

6 0

3 years ago

Pls help me for brainliest answer

Ket [755]

Answer with Step-by-step explanation:

$a)3n + 4 \\ \\n = 1 \\ 3 \times 1 + 4 \\ 3 + 4 \\ =7 \\ \\ n = 2 \\ 3 \times 2 + 4 \\ 6 + 4 \\ = 10 \\ \\ n = 3 \\ 3 \times 3 + 4 \\ 9 + 4 \\ = 13 \\ \\ n = 4 \\ 3 \times 4 + 4 \\ 12 + 4 \\ = 16 \\ \\ n = 10 \\ 3 \times 10 + 4 \\ 30 + 4 \\ = 34 \\$

So in this sequence,

1st term = 7

2nd term = 10

3rd term = 13

4th term = 16

10th term = 34

$b)4n - 5 \\ \\ n = 1 \\ 4 \times 1 - 5 \\ 4 - 5 \\ = - 1 \\ \\ n = 2 \\ 4 \times 2 - 5 \\ 8 - 5 \\ = 3 \\ \\ n = 3 \\ 4 \times 3 - 5 \\ 12 - 5 \\ = 7 \\ \\ n = 4 \\ 4 \times 4 - 5 \\ 16- 5 \\ = 11 \\ \\ n = 10 \\ 4 \times 10 - 5 \\ 40 - 5 \\ = 35$

In this sequence,

1st term = -1

2nd term = 3

3rd term = 7

4th term = 11

10th term =35

5 0

3 years ago