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Gnesinka [82]
3 years ago
11

guys honestly my day hasnt been that good but anyway here your daily free pints, hope you guys are having a good day keep your h

eads held up high kings and queens
Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

You have a nice day

Step-by-step explanation:

Don’t let anyone keep you down queen UwU

Rina8888 [55]3 years ago
6 0
Well everyone have bad and good days each day is a news day
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Given the replacement set {0, 1, 2,3 4,}, solve 6x - 3=3
IrinaVladis [17]

Answer:

1

Step-by-step explanation:

6x - 3 =3

6x =3 +3

6x =6

x=6 :6

x=1

7 0
4 years ago
You estimate that a jar contains 68 marbles.The actual number of marbles is 60.Find the percent error.Round your answer to the n
Ray Of Light [21]
8/60=13.333% approximately 13%
4 0
3 years ago
Simplify 8+6 over 7 - 3+1 over 2
sergejj [24]

Answer:

First, let's make an expression!

If you meant a different equation..sorry

\frac{8+6}{7-3} +\frac{1}{2}

Hope this is what you meant!

\frac{14}{4} +\frac{1}{2}\\\frac{7}{2} +\frac{1}{2} \\\frac{8}{2} =4

Hope this helps!

P.S. Stay Safe!

5 0
3 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
HI HURRY PLEASE also It us too hard to write please look at the picture​
Bas_tet [7]

Answer:

third one dowm

Step-by-step explanation:

its the answer

8 0
3 years ago
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