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Gnesinka [82]
3 years ago
11

guys honestly my day hasnt been that good but anyway here your daily free pints, hope you guys are having a good day keep your h

eads held up high kings and queens
Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

You have a nice day

Step-by-step explanation:

Don’t let anyone keep you down queen UwU

Rina8888 [55]3 years ago
6 0
Well everyone have bad and good days each day is a news day
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Bianca has a paper route. She delivers 100 newspapers every 2 days. How many newspapers does she deliver in a week?
Vlad [161]

We know Bianca delivers 100 newspapers every 2 days.

So we must find out how many papers she delivers in 1 day.

100 ÷ 2 = 50

Bianca delivers 50 papers in 1 day.

Now we must multiply that by 7.

50 × 7 = 350

We get 350 papers per week.

The answer is 350.

8 0
3 years ago
Jason complete 5/8 of his test and 10/25 of his homework. What fraction of his homework does he still need to complete?
sineoko [7]

Answer:

3/4

Step-by-step explanation:

Because the total homework would be 25/25

\frac{25}{25}-\frac{10}{25} =\frac{15}{25}

15/20 can be reduced to 3/4

4 0
3 years ago
2m - 16 + 5m +45 ( NEEDING BIG HELP ON UNIT :) )
MaRussiya [10]

Answer:

7m + 29

Step-by-step explanation:

You add 2m and 5m to get 7m

Then add -16  and 45 to get 29

4 0
3 years ago
The student to teacher ratio is 19:1 at school and there is a total of 400 students and teachers. How many teachers and how many
Jet001 [13]
Suppose there are 19x students, 1x teachers
19x+1x=400
20x=400
x=20
there are 20 teachers and 380 students. 
6 0
3 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
3 years ago
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