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3 years ago

What is the area of a trapezoid? 47,45,65

Mathematics

1 answer:

Masteriza [31]3 years ago

8 0

Area = 2,520m^2
(47+65)/2 = 56
56x45 = 2,520

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Cody bought two burgers and two

8_murik_8 [283]

Answer:

Step-by-step explanation:

Let the cost of one burger be $b while the cost of one small fries be s

2 burgers and 2 small fries cost $14

This means that;

2b + 2s = 14

divide both sides by 2

b + s = 7 •••••••• (i)

Three burgers and four small fries cost $23

Mathematically;

3b + 4s = 23 •••••••• (ii)

From i , we can see that s = 7- b

we can now substitute this into equation ii

3b + 4(7-b) = 23

3b + 28 -4b = 23

4b -3b = 28 -23

b = $5

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4 years ago

Simplify this e5 x e4

Gre4nikov [31]

Answer:

hope it will help you

Step-by-step explanation:

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3 years ago

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

--------------

Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is <em>True.</em>

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3 years ago

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Andreas93 [3]

Answer:

Step-tep explanation:

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3 years ago