Answer:
The polygon is a triangle, and is not a regular polygon.
Step-by-step explanation:
The polygon is a triangle because of it's three sides. It's also a non regular polygon since it's no equilateral or equiangular.
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
The correct answer is 7/9
Answer:
A = 12 ft
Step-by-step explanation:
Perimeter ( of SQUARE) B = 64
then each side = 64/4 = 16
AREA of SQUARE C = 400
side X side = 400
then side = sqrt 400
Now use Pyhtagorean Theorem to find leg of right triangle that is
side A Side B hypotenuse Side C
A^2 + 16^2 = (sqrt 400)^2
A^2 = 400 - 256
A^2 = 144 then A = 12 Ft
