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Tpy6a [65]
3 years ago
12

IREADY MATH LEVEL G HELP ASAP DUE AT 11:59!!

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0
I believe this is the answer

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Simplify the expression. 3−9 ∙ 36 ∙ 36
adell [148]

Answer:

the answer is 0

Step-by-step explanation:

4 0
2 years ago
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125% of what number is 80?<br> Oa 36<br> Oь 40<br> Os 64<br> Od 72
Mnenie [13.5K]

Answer:

d. 72

Step-by-step explanation:

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2 years ago
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The equation y=x^3 + 3 is symmetric with respect to which of he following?
lianna [129]

y = x^{3} +3

Subtract 3 from both sides,

y-3=x^{3}

Let x = X and y - 3 = Y

Then,

Y = X^{3}

So, we have shifted the origin to a point (0, 3).

This is an odd function and the graph of an odd function is symmetrical about the origin.

That is, symmetrical about X = 0, Y = 0

Symmetrical about x = 0,, y - 3 = 0

Symmetrical about x = 0, y = 3.

Hence, the graph is symmetrical about the point (0, 3).

3 0
2 years ago
The sum of the diagonals of a rhombus is 5√2.
Alex
Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC
= \frac{1}{2} BD (AO + OC)
\frac{1}{2} BD \times AC

So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}
BD \times AC = 8
Now, AC + \: BD = 5 \sqrt{2}

Squaring both sides, we get
AC {}^{2} + BD {}^{2} + 2 AC.BD =50
AC {}^{2} + BD {}^{2} + 2 \times 8 = 50
AC {}^{2} + BD {}^{2} = 50 - 16
AC {}^{2} + BD {}^{2} = 34

In △AOB, we have
OA {}^{2} + OB {}^{2} =AB {}^{2}
( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}
\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}
AC {}^{2} + BD {}^{2} = 4 AB {}^{2}
34 = 4 AB {}^{2}

Square rooting both sides
\sqrt{34} = 2 AB
Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units.

Hope it helps!

7 0
3 years ago
Two vehicles, a car and a truck, leave an intersection at the same time. The car heads east at an average speed of 70 miles per
forsale [732]

Step-by-step explanation:

[70,30] = 210 miles per hour

5 0
3 years ago
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