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2 years ago

What decimal is equivalent to 2/9?

Mathematics

2 answers:

tatuchka [14]2 years ago

5 0

2/9 into decimal.

9 divided by 2 = 4.5

BartSMP [9]2 years ago

5 0

0.2 / 0.22

it would've been 0.22222222 but if you cut it short its 0.2 or 0.22.

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A triangle is classified as an equilateral triangle when it has

Doss [256]

C. three sides with the same length

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3 years ago

Read 2 more answers

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Pi x 36 - 16 Need help on this please answer appropriate.

Bad White [126]

Answer:

To do this question, we must first convert Pi to a decimal form, as shown below:

Pi = 3.14

So then our equation becomes:

3.14 x 36 - 16

We still need to remember PEMDAS.

Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

So according to PEMDAS, we need to do 3.14 x 36, which equals 113.04

Now we have to do:

113.04 - 16 = 97.04

Our answer is 97.04

Hope this helps - genius423

4 0

3 years ago

A large cat at the zoo need to eat at least 14 pounds of raw meat each day. The zoo feeds the cat using cainsters that each cont

yan [13]

Answer:

14 ≤ 3.5 + 1.75c

Step-by-step explanation:

c = # canisters

14 ≤ 3.5 + 1.75c

10.5 ≤ 1.75c

c ≥ 6

4 0

2 years ago

What does the digit 2 represent in 701,280

dlinn [17]

Step-by-step explanation:

hundreds

3 0

3 years ago