Answer:
They will be 170 miles apart at 10 AM
Step-by-step explanation:
Nancy has 15´ of head start which is 1/4 hr.
NHD = 20*(1/4) = 5 miles is her head start
Mark leaves at 7.15hs = starting point
Marks stop at when they are 170 miles apart = t
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t = the time they are 170 miles apart
d= distance in miles Nancy travels in time t
170 - (d+5) = distance in miles Mark travels in time t
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Nancy's equation:
(1) d = 20t
Mark's equation:
(2) 170 - (d+5) = 40t
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(2) 170-d-5=40t
(2) d+40t=165
Substitute (1) into (2)
(2) 20t+40t=165
(2) 60t=165
(2) t=2.75
7:15 AM + 2.75 hrs (2:45hs) = 10 AM
They are 170 miles apart at 10 AM
check:
(1) d=20t
(1) d=20*2.75
(1) d=
55
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(2) 170 - (d+5) = 40t
(2) 170 - (d+5) = 40*2.75
(2) 170 - d-5 = 110
(2) d=55
Answer: 3’ 3”
Step-by-step explanation:
Answer:
2/3 < y < 6
Step-by-step explanation:
So what we want to do is get the equation to become just y surrounded by the gereater than signs. So we have 3y-4 and we first add 4 to all numbers. We now 2 < 3y < 18. WE can divide everything by 3 to get 2/3 < y < 6.
Answer:
because its an even number.
Step-by-step explanation:
Ex.
2x2=4
2+2=4
10x10=20
10+10=20
12x12=24
12+12=24
Answer:
40 km away.
Step-by-step explanation:
a^2 + b^2 = c^2
In this case, a = 16 * 2 = 32 km, since he travels 16 km per hour for 2 hours.
b = 12 * 2 = 24 km, since she travels 12 km per hour for 2 hours.
32^2 + 24^2 = c^2
1,024 + 576 = c^2
1600 = c^2
c^2 = 1600
c = plus or minus 40
Since distance cannot be negative, they will be 40 km away.
Hope this helps!
