All categories

3 years ago

The ordered pair below is from an inverse variation. Find the constant of variation. (7,8)

Mathematics

1 answer:

Marysya12 [62]3 years ago

4 0

Inverse variation: y = k/x. Here x=7 and y=8. Thus,

y = k/x becomes 8 = k/7, or k=56. The const. of var. is 56.

You might be interested in

Solve the inequality 2x – 5 > 7<br> a. x>6<br> b. x >12<br> c. x

julsineya [31]

You start with 2x -5>7 the you add five to both sides 2x-5+5>7 +5 2x.12 then divide both sides by 2 2x divided by 2 > and 12 divided by 2 and get x>6

3 0

3 years ago

A) What is the domain and range of the graph? (Use the equations editor or explain)

riadik2000 [5.3K]

The domain: -5 < x ≤ 1 and the range: -3 ≤ y ≤ 1 is a function. b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The domain of a relation is the set of values of the independent variable for a defined function.

The domain is the horizontal extent of the graph.

The range of a relation is the set of values of the dependent variable for a defined function.

The range is the vertical extent of the graph.

The vertical line can intersect the graph in at most one place.

This graph extends from x > -5 to x = 1.

The domain

-5 < x ≤ 1 ------ (-5, 1] in interval notation

This graph extends from y = -3 to y = 1.

The left side of the graph does not include the point (-5, 1), but the right side includes the point (1, 1).

y = 1 is one of the output values of the relation.

The range

-3 ≤ y ≤ 1 . . . . . . . . [-3, 1] in interval notation

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

Learn more about the domain and range of the function:

brainly.com/question/2264373

#SPJ1

8 0

2 years ago

HELP ME <br> solve for the right triangle

VikaD [51]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent ratios in the right triangle

cos41° = $\frac{adjacent}{hypotenuse}$ = $\frac{VW}{VX}$ = $\frac{7}{VX}$

Multiply both sides by VX

VX × cos41° = 7 ( divide both sides by cos41° )

VX = $\frac{7}{cos41}$ ≈ 9.3

-----------------------------------------------------------------------

tan41° = $\frac{opposite}{adjacent}$ = $\frac{WX}{VW}$ = $\frac{WX}{7}$

Multiply both sides by 7

7 × tan41° = WX, thus

WX ≈ 6.1

-------------------------------------------------------------------------

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180° for ∠ X

∠ X = 180° - (90 + 41)° = 180° - 131° = 49°

3 0

3 years ago

Apply the distributive property to factor out the greatest common factor 22c+33d

Tems11 [23]

What you need to do is find a common multiple which is 11, Then you divide 22c and 33d by 11 so you get 2c and 3d Then since there is an addition sign you put 2c and 3d is ()
The Final answer is
11(2c+3d)

5 0

3 years ago

What are the multiplication sentences for factors of 6?

mart [117]

Answer:

keep doubling the answer by 6

7 0

3 years ago